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dalvyx [7]
3 years ago
14

Write a hypothesis about the use of an object’s physical characteristics to determine its density. Use the format "if . . . then

. . . because . . .” and be sure to answer the lesson question "How can the density of an object be determined?”
Physics
2 answers:
IRINA_888 [86]3 years ago
7 0

Explanation:

The density of an object is given by its mass divided by its volume. It is denoted by d or ρ. It is given by :

\rho=\dfrac{m}{V}

It the mass and volume of an object is known then it is easier to find its density. It is directly proportional to the mass and inversely proportional to the volume of that object.

If the mass of an object increases, its density will increase because the mass and density are directly proportional to each other.

And if the volume of an object increases, it density will decrease because the volume and density are inversely proportional to each other.    

mash [69]3 years ago
5 0
For this case you must first know the definition of density.
 D = m / v
 where,
 m: mass
 v: volume.
 You can then write the following hypothesis:
 IF you know two physical characteristics of an object then you can determine the density. First weigh the object, THEN measure its volume BECAUSE the density is the quotient between the mass and the volume of an object.
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2 years ago
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A boy standing throws a penny horizontally at 7.25 m/s out of the window of his apparent buliding. If the window is 10.0 m above
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Answer:

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a = -9.8 m/s/s

t = ? (we need to find the time in this dimension so we can use it in the x dimension to find the displacement, our unknown)

In the "x-stuff" category:

v₀ = 7.25 m/s (this is given)

Δx = ???

a = 0 (acceleration in this dimension is ALWAYS 0)

t = (we will solve for this in the y-dimension and plug it in here).

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Δx = v₀t + \frac{1}{2}at^2 and plugging in from the y-dimension info:

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t = 1.4 seconds

Now we will do the same in the x-dimension, using t = 1.4:

Δx = v₀t + \frac{1}{2}at^2 and filling in the x-stuff:

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Δx = 7.25(1.4) + 0 so

Δx = 1.0 × 10¹ m (That's rounded correctly to 2 sig dig's: 10 m from the base of the building).

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