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dalvyx [7]
3 years ago
14

Write a hypothesis about the use of an object’s physical characteristics to determine its density. Use the format "if . . . then

. . . because . . .” and be sure to answer the lesson question "How can the density of an object be determined?”
Physics
2 answers:
IRINA_888 [86]3 years ago
7 0

Explanation:

The density of an object is given by its mass divided by its volume. It is denoted by d or ρ. It is given by :

\rho=\dfrac{m}{V}

It the mass and volume of an object is known then it is easier to find its density. It is directly proportional to the mass and inversely proportional to the volume of that object.

If the mass of an object increases, its density will increase because the mass and density are directly proportional to each other.

And if the volume of an object increases, it density will decrease because the volume and density are inversely proportional to each other.    

mash [69]3 years ago
5 0
For this case you must first know the definition of density.
 D = m / v
 where,
 m: mass
 v: volume.
 You can then write the following hypothesis:
 IF you know two physical characteristics of an object then you can determine the density. First weigh the object, THEN measure its volume BECAUSE the density is the quotient between the mass and the volume of an object.
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Answer:

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Explanation:

Suppose Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by

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Given that,

Kinetic energy = 6.2 MeV

Radius = 0.500 m

We need to calculate the acceleration

Using formula of acceleration

a=\dfrac{v^2}{r}

Put the value into the formula

a=\dfrac{\dfrac{1}{2}mv^2}{\dfrac{1}{2}mr}

Put the value into the formula

a=\dfrac{6.2\times10^{6}\times1.6\times10^{-19}}{\dfrac{1}{2}\times1.67\times10^{-27}\times0.51}

a=2.32\times10^{15}\ m/s^2

We need to calculate the rate at which it emits energy because of its acceleration is

\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}

Put the value into the formula

\dfrac{dE}{dt}=\dfrac{(1.6\times10^{-19})^2\times(2.3\times10^{15})^2}{6\pi\times8.85\times10^{-12}\times(3\times10^{8})^3}

\dfrac{dE}{dt}=3.00\times10^{-23}\ J/s

The energy in ev/s

\dfrac{dE}{dt}=\dfrac{3.00\times10^{-23}}{1.6\times10^{-19}}\ J/s

\dfrac{dE}{dt}=1.875\times10^{-4}\ ev/s

We need to calculate the fraction of its energy that it radiates every second

\dfrac{\dfrac{dE}{dt}}{E}=\dfrac{1.875\times10^{-4}}{6.2\times10^{6}}

\dfrac{\dfrac{dE}{dt}}{E}=3.02\times10^{-11}

Hence, The fraction of its energy that it radiates every second is 3.02\times10^{-11}.

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Explanation:

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This ultimately implies that, the rotation of earth refers to the time taken by earth to rotate once on its axis. One spinning movement of the earth on its axis takes approximately 24 hours to complete with respect to the sun. Thus, this makes us to experience day and night (sun rise and sun set) due to the rotation of planet about its axis.

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8 0
3 years ago
One object is thrown vertically upward with an initial velocity of 100 m/s and
gavmur [86]

We have that for the Question it can be said that The maximum height reached  by the first <em>object</em> will be  100 times  that of the other.

  • (H_{max})_1=100*(H_{max})_2

From the question we are told

One object is thrown vertically upward with an initial velocity of 100 m/s and  another object with an initial velocity of 10 m/s. The maximum height reached  by the first object will be

that of the other.

a. 10,000 times

b. none of these

<em>c. </em><em>1000 times</em>

d. 100 times

<em>e.</em><em> 10 times</em>

Generally the equation for the velocity is mathematically given as

v=\frac{d}{t}\\\\Where\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{(V_1)^2}{(v_2)^2}\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{10000}{(10}\\\\

(H_{max})_1=100*(H_{max})_2

Therefore

The maximum height reached  by the first <em>object</em> will be  100 times  that of the other.

(H_{max})_1=100*(H_{max})_2

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