Explanation:
Let us assume that piece 1 is
is facing west side. And, piece 2 is
facing south side.
Let
= m and
= 2m. Hence,
![2mv_{3y} = m(21)](https://tex.z-dn.net/?f=2mv_%7B3y%7D%20%3D%20m%2821%29)
![v_{3y} = \frac{21}{2}](https://tex.z-dn.net/?f=v_%7B3y%7D%20%3D%20%5Cfrac%7B21%7D%7B2%7D)
= 10.5 m/s
![2mv_{3x} = m(21)](https://tex.z-dn.net/?f=2mv_%7B3x%7D%20%3D%20m%2821%29)
![v_{3x} = \frac{21}{2}](https://tex.z-dn.net/?f=v_%7B3x%7D%20%3D%20%5Cfrac%7B21%7D%7B2%7D)
= 10.5 m/s
![v_{3} = \sqrt{v^{2}_{3x} + v^{2}_{3y}}](https://tex.z-dn.net/?f=v_%7B3%7D%20%3D%20%5Csqrt%7Bv%5E%7B2%7D_%7B3x%7D%20%2B%20v%5E%7B2%7D_%7B3y%7D%7D)
= ![\sqrt{(10.5)^{2} + (10.5)^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%2810.5%29%5E%7B2%7D%20%2B%20%2810.5%29%5E%7B2%7D%7D)
= 14.84 m/s
or, = 15 m/s
Hence, the speed of the third piece is 15 m/s.
Now, we will find the angle as follows.
![\theta = tan^{-1} (\frac{v_{3y}}{v_{3x}})](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%5E%7B-1%7D%20%28%5Cfrac%7Bv_%7B3y%7D%7D%7Bv_%7B3x%7D%7D%29)
= ![tan^{-1}(\frac{10.5}{10.5})](https://tex.z-dn.net/?f=tan%5E%7B-1%7D%28%5Cfrac%7B10.5%7D%7B10.5%7D%29)
= ![tan^{-1} (45^{o})](https://tex.z-dn.net/?f=tan%5E%7B-1%7D%20%2845%5E%7Bo%7D%29)
= ![45^{o}](https://tex.z-dn.net/?f=45%5E%7Bo%7D)
Therefore, the direction of the third piece (degrees north of east) is north of east.
Answer:
Angle of refraction
Explanation:
The incident ray is the ray before it reaches the surface.
The refracted ray is the ray after it reaches the surface.
n₁ is called the index of incidence.
n₂ is called the index of refraction.
θ₁ is called the angle of incidence.
θ₂ is called the angle of refraction.
They are related by Snell's law:
n₁ sin θ₁ = n₂ sin θ₂
V = IR
I = current
R = resistance
Voltage = 100 * (3.44x 10^-4) = do the calculation
Hope this helps
The answer is: the building codes, which are a set of rules that regulate the conditions that a building must meet. Those requirements are very important to guarantee safety of both the people who are building it and the people who are going to work or live inside of the building in the future
<h3>Solution for the above question : -</h3>
Ohm's law states that :
the terms used are :
let's solve for electric current :
![\mathfrak{good\: \: luck \: \: for \: \: your \: \: assignment}](https://tex.z-dn.net/?f=%5Cmathfrak%7Bgood%5C%3A%20%20%5C%3A%20luck%20%5C%3A%20%20%5C%3A%20for%20%5C%3A%20%20%5C%3A%20your%20%5C%3A%20%20%5C%3A%20assignment%7D)