Answer:
6.43 moles of NF₃.
Explanation:
The balanced equation for the reaction is given below:
N₂ + 3F₂ —> 2NF₃
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of NF₃.
Finally, we shall determine the number of mole of nitrogen trifluoride (NF₃) produced by the reaction of 9.65 moles of Fluorine gas (F₂). This can be obtained as follow:
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of NF₃.
Therefore, 9.65 moles of F₂ will react to to produce = (9.65 × 2)/3 = 6.43 moles of NF₃.
Thus, 6.43 moles of NF₃ were obtained from the reaction.
The correct answer is Oxyanion Nitrite. Oxyanion is referred to as an ion which contains one or more oxygen atoms that are bonded to another chemical element. It has a generic formula of <span>A. </span>x<span>O </span>z− <span>y, wherein A, stands for a chemical element, while O, stands for an Oxygen atom</span>
El número de Avogadro es 6,022 x 10^23, y es el número de átomos que hay en un mol de dicho elemento. A su vez un mol es la cantidad de un elemento cuya masa en gramos coincide con el peso atómico.
Por tanto, 6,022 x 10^23 átomos del elemento tienen una masa en gramos igual a su peso atómico. Hacemos una regla de tres:
1 gramo -------- 1,5 x 10^22 átomos
x ------------------ 6,022 x 10^23 átomos
=> x = 40,1 gramos por mol del elemento.
De modo que su peso atómico es 40,1. Se trata del calcio.
Saludos.
The number of mole of nitrogen that occupies 1.2 L under the same condition is 0.6 mole
<h3>Data obtained from the question </h3>
- Initial mole (n₁) = 0.2 mole
- Initial volume (V₁) = 0.4 L
- Final volume (V₂) = 1.2 L
- Final mole (n₂) =?
<h3>How to determine the final mole </h3>
The final mole can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both side n
PV / n = RT
Divide both side by P
V / n = RT / P
RT / P = constant
V / n = constant
Thus,
V₁ / n₁ = V₂ / n₂
0.4 / 0.2 = 1.2 / n₂
2 = 1.2 / n₂
Cross multiply
2 × n₂ = 1.2
Divide both side by 2
n₂ = 1.2 / 2
n₂ = 0.6 mole
Learn more about ideal gas equation:
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