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elena-s [515]
3 years ago
10

M. elementcenabrecht0.5 mele of an​

Chemistry
1 answer:
drek231 [11]3 years ago
5 0

Answer:

Number of moles (n)=

molecular weight

weight

Weight=n×Molecular weight

=0.5×14

Mass=7g

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In the equation. C + O2 --------> CO2; CO2 is the
lubasha [3.4K]

Answer: Product

Explanation:

A Chemical reaction shows how substances, written in symbols  known as  reactants, are converted to different substances called products. An arrow from the left hand side (reactants) points to right hand side ( products )shows the direction of  flow of reaction.

In the equation. C + O2 --------> CO2

                             reactant------> product

CO2  is the product

7 0
3 years ago
A bottle of wine contains 9.81 grams of C2H5OH, dissolved in 87.5 grams of water. The final volume of the solution is 100.0 mL.
dimulka [17.4K]

Answer:

[EtOH] = 2.2M and Wt% EtOH = 10.1% (w/w)

Explanation:

1. Molarity = moles solute / Volume solution in Liters

=> moles solute = mass solute / formula weight of solute = 9.8g/46g·mol⁻¹ = 0.213mol EtOH

=> volume of solution (assuming density of final solution is 1.0g/ml) ...

volume solution =  9.81gEtOH + 87.5gH₂O = 97.31g solution x 1g/ml = 97.31ml = 0.09731 Liter solution

Concentration (Molarity) = moles/Liters = 0.213mol/0.09731L = 2.2M in EtOH

2. Weight Percent EtOH in solution (assuming density of final solution is 1.0g/ml)

From part 1 => [EtOH] = 2.2M in EtOH = 2.2moles EtOH/1.0L soln

= {(2.2mol)(46g/mol)]/1000g soln] x 100% = 10.1% (w/w) in EtOH.

3 0
3 years ago
The table below shows the role of different substances during photosynthesis.
RoseWind [281]
A I think I could be wrong I’m not good at this
6 0
3 years ago
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AlekseyPX

Answer:

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4 0
3 years ago
How would you prepare 3.5 L of a 0.9M solution of KCl?
PolarNik [594]
V=3,5L\\
Cm=0,9M\\
M_{KCl}=74\frac{g}{mol}\\\\
C_{m}=\frac{n}{V}\\\\
n=\frac{m}{M}\\\\
C_{m}=\frac{m}{MV} \ \ \ \Rightarrow  \ \ \ m=C_{m}MV\\\\
m=0,9\grac{mol}{L}*74\frac{g}{mol}*3,5L=233,1g

B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark. 
4 0
3 years ago
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