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svlad2 [7]
3 years ago
5

In a certain company, all employees are either beta employees or standard employees. In this company, 25% of the beta employees

and 17% of the standard employees participate in the voluntary equity program. Let S be the number of standard employees. If there are 600 employees total, what is the value of S?
Mathematics
1 answer:
marissa [1.9K]3 years ago
4 0

In addition to the question, the following conditions must be met:

(1) M > 100

(2) more than 130 employees participate in the voluntary equity program

Answer:

Value of A is 200

Step-by-step explanation:

In this scenario when we divide 100 by the percentage of each employee category we will get a proportion that the number of employees must obey.

This is illustrated below:

For Beta employees 100/25= 4

So the number of employees that are Beta must be divisible by 4

For Standard employees 100/17 = 5.882

Since fractions of employees cannot be obtained, in this case the number of employees must be a multiple of 100

Total employees are 600

The various combinations are:

1. Beta employees 500 and Standard employees 100

Survey participants= (0.25 * 500) + (0.17 * 100) = 142

Number of participants is okay as it is >130 but does not satisfy Standard employees being >100

2. Beta employees are 300 and Standard employees are 300

Survey participants = (0.25 * 300) + (0.17 * 300) = 126

This does not satisfy condition of survey participants >130

3. Beta employees 400 and Standard employees 200

Survey participants = (0.25 * 400) + (0.17 * 200) = 134

This satisfies conditions of >130 survey participants and Standard employees >100

So correct value of S is 200

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Answer:

(a)

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

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(b)

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<u><em>Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes</em></u>

(b)  Now want to know when the two pools would have the same amount of water.  If they have the same amount of water then you can express:

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