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Ne4ueva [31]
3 years ago
7

After a massive-star supernova, what is left behind?.

Physics
1 answer:
scoray [572]3 years ago
8 0

Answer: A <u>Nebula </u>is left behind. A spectacular explosion in which a star ejects most of its mass in a violently expanding cloud of debris.

Hope this helps!

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Both Slicing a tomato and a chemical change has a burning toast cannot be reversed. however, why is slicing a tomato still consi
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Because the tomato did not chemically changed it was only physically altered.

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4 years ago
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A small rock is thrown straight up from the edge of the roof of an 8.00 m tall building with an initial speed vo . The speed of
Serjik [45]

Answer:

20.47 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² = a

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{24^2-0^2}{2\times 9.81}\\\Rightarrow s=29.3577\ m

Total height of the fall is 29.3577 m

Height the ball reached above the building is 29.3577-8=21.3577\ m

s=ut+\frac{1}{2}at^2\\\Rightarrow 21.3577=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{21.3577\times 2}{9.81}}\\\Rightarrow t=2.0866\ s

Time taken to reach the point from where the ball was thrown is 2.0866 s

This will also be the time it takes the ball to reach the maximum height

s=ut+\frac{1}{2}at^2\\\Rightarrow u=\dfrac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\dfrac{21.3577-\frac{1}{2}\times -9.81\times 2.0866^2}{2.0866}\\\Rightarrow u=20.47\ m/s

The initial velocity with which the rock was thrown was 20.47 m/s

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3 years ago
Which two labeled points on the fig are out of phase by 180° ?
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You can use the points of answer:

B and F
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