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Ne4ueva [31]
3 years ago
7

After a massive-star supernova, what is left behind?.

Physics
1 answer:
scoray [572]3 years ago
8 0

Answer: A <u>Nebula </u>is left behind. A spectacular explosion in which a star ejects most of its mass in a violently expanding cloud of debris.

Hope this helps!

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Astronaut Rob leaves Earth in a spaceship at a speed of 0.960c relative to an observer on Earth. Rob's destination is a star sys
xxMikexx [17]

Answer:

A) 15.0 years

Explanation:

Due to the distance to the star system is in light-year units, we can compute the time by using:

t=\frac{d}{v}=\frac{14.4 l-y}{0.960}=15l-y

then, Rob will take to complete the trip about 15 light-years.

hope this helps!!

3 0
3 years ago
What is the maximum wavelength of incident light that can produce photoelectrons from silver? The work function for silver is Φ=
Oksi-84 [34.3K]

Answer:

The maximum wavelength of incident light that can produce photoelectrons from silver is 423.5 nm.

Explanation:

Given;

work function of silver, Φ = 2.93 eV = 2.93 x 1.602 x 10⁻¹⁹ J = 4.6939 x 10⁻¹⁹ J

Apply Einstein Photo electric effect;

E = K.E + Ф

Where;

E is the energy of the incident light

K.E is the kinetic of electron

Ф is the work function of silver surface

For the incident light to have maximum wavelength, the kinetic energy of the electron will be zero.

E = Ф

hf = Ф

h\frac{c}{\lambda} = \phi

where;

c is speed of light = 3 x 10⁸ m/s

h is Planck's constant, = 6.626 x 10⁻³⁴ J/s

λ is the wavelength of the incident light

\lambda = \frac{hc}{\phi}\\\\\lambda =\frac{6.626*10^{-34} *3*10^8}{4.6939*10^{-19}} \\\\\lambda = 4.235 *10^{-7} \ m\\\\\lambda = 423.5 *10^{-9} \ m\\\\\lambda = 423.5 \ nm

Therefore, the maximum wavelength of incident light that can produce photoelectrons from silver is 423.5 nm.

8 0
3 years ago
First law of equilibrium
valentina_108 [34]

Answer:

For an object to be an equilibrium it must be experiencing no acceleration.

Explanation:

Hope it helps.

5 0
3 years ago
A satellite is orbiting earth at a distance of 35.0 kilometers. The satellite has a mass of 500 kilograms. What is the force bet
Alika [10]

Answer:

F = 4856.32 N

Explanation:

Given,

A satellite is orbiting earth at a distance from Earth surface, h = 35000 m

The mass of the satellite, m = 500 Kg

The radius of the Earth, R = 6.371 x 10⁶ m

The mass of the Earth, M = 5.972 x 10²⁴ Kg

The gravitational constant, G = 6.67408 x 10 ⁻¹¹ m³ kg⁻¹ s⁻²

The force between the Earth and the satellite is given by the formula

                                    F = GMm/(R+h)²  N

Substituting the values in the above equation

        F = (6.67408 x 10 ⁻¹¹ X 5.972 x 10²⁴ X 500) / (6.371 x 10⁶ + 35000)²

                                        = 4856.32 N

Hence,  the force between the planet and the satellite is, F = 4856.32 N

5 0
3 years ago
Does a battery produce dc or ac? does the generator at a commercial power station produce dc or ac?
Art [367]
1) dc
2) ac

Because my dad said so
8 0
3 years ago
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