Using:
v = Aωcos(ωt), at t = 0, A = 2.3 m and v = 15 m/s
ω = 15/2.3
ω = 6.52 rad/s
Answer:
v = 6295.55 m/s
Explanation:
Given that,
The radius of a planet,
The free fall acceleration of the planet, a = 7.45 m/s²
We need to find the tangential speed of a person standing at the equator.
Also, the centripetal acceleration was equal to the gravitational acceleration at the equator.
We know that,
Centri[etal acceleration,
So, the tangential speed of the person is equal to 6295.55 m/s.
Answer: Strength of magnet and distance from magnetic material
Explanation:
The potential energy of a magnet is determined by the strength of the magnet and the distance between a magnet and another magnet or a magnetic material. Magnetic materials are materials that would be attracted when brought close to a magnet, example of magnetic materials are most metals.
Answer:
C 340 m
Explanation:
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Answer:
The momentum of block B = 27 Kg m/s
Explanation:
Given,
The initial momentum of block A, MU = 15 Kg m/s
The final momentum of block A, MV = -12 Kg m/s
Consider the block B is initially at rest.
Therefore, the initial momentum of block B, mu = 0
According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.
<em> MU + mu = MV + mv</em>
15 + (0) = (-12) + mv
mv = 15 + 12
= 27 Kg m/s
Hence, the momentum of the block B after impact is, mv = 27 Kg m/s