Answer:
H(angular momentum) = I * ω inertia * angular speed
ω = V / R = 5 m/s / .2 m = 25 / s
I = M R^2 = 2 kg * (.2 m)^2 = .08 kg-m^2
H = 25 / s * .08 kg-m^2 = 2 kg-m^2/s
Using the right hand rule - the angular momentum is towards the west - the same direction as the angular velocity
Answer:
option E
Explanation:
given,
I is moment of inertia about an axis tangent to its surface.
moment of inertia about the center of mass
.....(1)
now, moment of inertia about tangent
...........(2)
dividing equation (1)/(2)
the correct answer is option E
We would have to use wind or another source
Because: Some of the work done by the machine is used to overcome the friction created by the use of the machine. ... Work output can never be greater than work input. Machines allow force to be applied over a greater distance, which means that less force will be needed for the same amount of work.
<span>Since youc oncetrate all your force directly towards the moment arm it means that you push it at an angle of your force is directed to the left or the right and I bet that it must be 90</span> degrees to the bar. Obviuosly, if you are about to push it you will do it straight up but not in a zig zag way. In other words, it should be perpendicular to the arm because the<span> torque can be produced only if force is applied at a constant index (90).
Hope that helps! Regards.</span>
