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Pani-rosa [81]
3 years ago
8

Which element could provide one atom to make an ionic bond with nitrogen?​

Physics
1 answer:
aev [14]3 years ago
8 0

Answer:

boron

aluminum

gallium

indium

thallium

Explanation:

Any of these could work. Nitrogen has 5 valence electrons so you just needed to pick an element that has 3 valence electrons that nitrogen could borrow. This periodic table shows valence electron counts:

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To appreciate the strength of gravity, calculate the number of steel cables that would be required, in the absence of gravity, t
Serga [27]

Answer:

N=5.36*10^{17}

Explanation:

From the question we are told that:

Tensile strength of steel \sigma_c=370 MPa.=370*10^6

Cross-sectional area A= 1m^2

Generally the equation for Total Force is mathematically given by

 F = \frac{G M m}{r^2}

 F=\frac{6.67*10^{-11}*7.35*10^{22}*5.97*10^{24}}{(384*10^3)^2}

Since this is the force of each cable

 F=\sigma_c NA

 F= 370*10^6*N*1

Therefore

 370*10^6*N*1=\frac{6.67*10^{-11}*7.35*10^{22}*5.97*10^{24}}{(384*10^3)^2}

 N=5.36*10^{17}

4 0
3 years ago
Being underinsured is one of the main reasons that some people are unable to get quality health care. Please select the best ans
liberstina [14]

The answer to this question is True.

7 0
3 years ago
Read 2 more answers
Why are people so rude???
DanielleElmas [232]

Answer:

I.D.K but the same measure they use to judge will be used to judge them

Explanation:

6 0
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Earth's gravitational force just got three times stronger! What happens to your weight?
kicyunya [14]

Your "weight" is the name you give to that gravitational force.
So your question actually says:

           "Your weight just got three times stronger !
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8 0
3 years ago
A 90 kg ice skater moving at 12.0 m/s on the ice encounters a region of roughed up ice with a coefficient of kinetic friction of
balandron [24]

Answer:

The skater covers a distance of <u>15 m</u> before stopping.

Explanation:

Let the distance traveled before stopping be 'd' m.

Given:

Mass of the skater (m) = 90 kg

Initial velocity of the skater (u) = 12.0 m/s

Final velocity of the skater (v) = 0 m/s (Stops finally)

Coefficient of kinetic friction (μ) = 0.490

Acceleration due to gravity (g) = 9.8 m/s²

Now, we know that, from work-energy theorem, the work done by the net force on a body is equal to the change in its kinetic energy.

Here, the net force acting on the skater is only frictional force which acts in the direction opposite to motion.

Frictional force is given as:

f=\mu N

Where, 'N' is the normal force acting on the skater. As there is no vertical motion, N=mg

∴ f=\mu mg=0.490\times 90\times 9.8=432.18\ N

Now, work done by friction is a negative work as friction and displacement are in opposite direction and is given as:

W=-fd=-432.18d

Now, change in kinetic energy is given as:

\Delta K=\frac{1}{2}m(v^2-u^2)\\\\\Delta K=\frac{1}{2}\times 90(0-12^2)\\\\\Delta K=45\times (-144)=-6480\ J

Therefore, from work-energy theorem,

W=\Delta K\\\\-432.18d=6480\\\\d=\frac{6480}{432.18}\\\\d=14.99\approx 15\ m

Hence, the skater covers a distance of 15 m before stopping.

7 0
3 years ago
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