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TiliK225 [7]
3 years ago
10

How would adding the catalyst nitrogen monoxide (NO) affect this reaction?

Chemistry
2 answers:
steposvetlana [31]3 years ago
6 0

If nitrogen monoxide (NO) is added to 2SO2(g) + O2(g) → 2SO3(g),

it will react with O2 and decrease the reaction rate by lowering the amount of O2.  So the answer is C.  NO decreases collisions between the SO2 and O2 molecules.

asambeis [7]3 years ago
5 0

Answer: A.  NO increases the rate at which SO_3 molecules are formed.

Explanation: The catalyst makes it possible for the reaction to take place by another path that makes possible reaction at a lower energy.

Activation energy is the extra energy that must be supplied to reactants in order to cross the energy barrier and thus convert to products.

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more reactants (SO_2) and (O_2) undergo collision and can cross the energy barrier and convert to products (SO_3)

Thus NO increases the rate at which SO_3 molecules are formed.

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How to know that it has a high boiling point based on the question
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<h2>Explanations</h2>

The complete balanced equation for the given reaction is expressed as;

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\begin{gathered} moles\text{ of CH}_4=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CH}_4=\frac{0.0059}{16.04} \\ moles\text{ of CH}_4=0.000368moles \end{gathered}

According to stoichimetry, 1 mole of methane produces 2 moles of water, hence the moles of water required will be:

\begin{gathered} moles\text{ of H}_2O=\frac{2}{1}\times0.000368 \\ moles\text{ of H}_2O=0.000736moles \end{gathered}

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\begin{gathered} Mass\text{ of H}_2O=moles\times molar\text{ mass} \\ Mass\text{ of H}_2O=0.000736\times18.02 \\ Mass\text{ of H}_2O=0.0133grams=1.33\times10^{-2}grams \end{gathered}

Therefore the mass of water produced from the complete combustion of 5.90×10−3 g of methane is 1.33 * 10^-2grams

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