Answer:
120 mol Mg
General Formulas and Concepts:
<u>Chemistry - Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
120 moles H₂
<u>Step 2: Identify Conversions</u>
RxN: 3 mol H₂ = 3 mol Mg
<u>Step 3: Stoichiometry</u>
<u />
= 120 mol Mg
Hey There!
To solve this question remember that 1 mole of ammonia is equal to 17G of ammonia.
Using that, we first multiply 17 by 7 = 24
Then we multiply 7 by .27 = 1.89
Finally, taking those and adding them together gives you the answer...
<u>25.89 grams :)</u>
<u></u>
<u>Have a great day, I hope I helped.</u>
<u></u>
<u>+ Brainliest & Five stars are always appreciated </u>
Synthesis. Iodine monobromide is formed when iodine and bromine are combined in a chemical reaction: I2 + Br2 → 2 IBr.
Answer:
The thermal energy (heat) needed, to raise the temperature of oil of mass 'm' kilogram and specific heat capacity 'c' from 20°C to 180°C is 160·m·c joules
Explanation:
The heat capacity, 'C', of a substance is the heat change, ΔQ, required by a given mass, 'm', of the substance to produce a unit temperature change, ΔT
∴ C = ΔQ/ΔT
ΔQ = C × ΔT
C = m × c
Where;
c = The specific heat capacity
ΔT = The temperature change = T₂ - T₁
∴ ΔQ = m × c × ΔT
Therefore, the thermal energy (heat) needed, ΔQ, to raise the temperature of oil of mass 'm' kilogram and specific heat capacity, 'c' from 20°C to 180°C is given as follows;
ΔQ = m × c × (180° - 20°) = 160° × m·c
ΔQ = 160·m·c joules
If we use 100 grams of compound:
m(C) = 0,7787 · 100 g = 77,87 g.
n(C) = 77,87 g ÷ 12 g/mol = 6,49 mol.
m(H) = 0,0263 · 100 g = 2,63 g.
n(H) = 2,63 g ÷ 1 g/mol = 2,63 mol.
m(O) = 0,5562 · 100 g = 55,62 g.
n(O) = 55,62 g ÷ 16 g/mol = 3,48 mol.
n(C) : n(H) : n(O) = 6,49 mol : 2,63 mol : 3,48 mol.
n(C) : n(H) : n(O) = 2,5 : 1 : 1,33.
From molecular mass only possible is C₁₂H₉O₁₂.
