Explanation:
the pressure is given by P=hpg
where h is height,p is density, g is 10m/s²
thus P= 0.05m•13.6x10³•10
P=6.8x10³ Hgmm
A elephant kicks a 5.0\,\text {kg}5.0kg5, point, 0, start text, k, g, end text stone with 150\,\text J150J150, start text, J, en
S_A_V [24]
The speed of the stone is 7.7 m/s
Explanation:
The kinetic energy of a body is the energy possessed by the body due to its motion. Mathematically,
where
m is the mass of the body
v is its speed
For the stone in this problem, we have:
K = 150 J is its kinetic energy
m = 5.0 kg is its mass
Re-arranging the equation for v, we find the speed of the stone:
Learn more about kinetic energy:
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Explanation:
Not being able to see the picture attached and supposing the ground level is considered to be the water level so to be able to find out the velocity you need to score into the hoop you need to use the combined force ( resulting force) to throw the ball at 6.50 m distance, 1 m below to where you are standing
Answer:
V = -RC (dV/dt)
Solving the differential equation,
V(t) = V₀ e⁻ᵏᵗ
where k = RC
Explanation:
V(t) = I(t) × R
The Current through the capacitor is given as the time rate of change of charge on the capacitor.
I(t) = -dQ/dt
But, the charge on a capacitor is given as
Q = CV
(dQ/dt) = (d/dt) (CV)
Since C is constant,
(dQ/dt) = (CdV/dt)
V(t) = I(t) × R
V(t) = -(CdV/dt) × R
V = -RC (dV/dt)
(dV/dt) = -(RC/V)
(dV/V) = -RC dt
∫ (dV/V) = ∫ -RC dt
Let k = RC
∫ (dV/V) = ∫ -k dt
Integrating the the left hand side from V₀ (the initial voltage of the capacitor) to V (the voltage of the resistor at any time) and the right hand side from 0 to t.
In V - In V₀ = -kt
In(V/V₀) = - kt
(V/V₀) = e⁻ᵏᵗ
V = V₀ e⁻ᵏᵗ
V(t) = V₀ e⁻ᵏᵗ
Hope this Helps!!!
Answer:
a. 2N
b. 12N
c. 20N
Explanation:
Dtaa given,
Weight of rock in air=10N
weight of rock in water =8N
a. When the rock is suspend in water, it will displace some water from thr container since Buoyant force is the acts upward and equals in magnitude to the volume of water displays,
The buoyant force is calculated as 10N-8N=2N
b. The scale reading will be the sum of the buoyant force and the weight of the container
scale reading =10N+2N=12N
c. When the rock rest at the bottom of the container, the weight of the rock(10N) is acting downward and the weight of the container also is acting downward. Hence the sum of the two weight gives the reading on the scale
scale reading=10N+10N=20N
