Fusion occurs in the Sun's core, releasing energy that is transferred outward. Once in the radiative zone, gamma rays are transferred by radiation. They are converted to other types of photons, which move into the convective zone, where they are transferred by convection. Finally, energy is emitted from the photosphere.
Answer:
1. The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.
2. The person's image is 3.38 m tall.
Explanation:
From the given question, object distance, u = 0.75 m, object height = 1.8 m, radius of curvature of the reflecting globe, r = 8 cm = 0.08 m.
f =
=
= 0.04 m
1. The image distance, v, can be determined by applying mirror formula:
=
+ ![\frac{1}{v}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bv%7D)
=
+ ![\frac{1}{v}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bv%7D)
-
= ![\frac{1}{v}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bv%7D)
= ![\frac{4 - 75}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B4%20-%2075%7D%7B100%7D)
= - ![\frac{71}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B71%7D%7B100%7D)
⇒ v = -![\frac{100}{71}](https://tex.z-dn.net/?f=%5Cfrac%7B100%7D%7B71%7D)
= - 1.41 m
The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.
2.
= ![\frac{image height}{object height}](https://tex.z-dn.net/?f=%5Cfrac%7Bimage%20height%7D%7Bobject%20height%7D)
= ![\frac{v}{1.8}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%7D%7B1.8%7D)
v = ![\frac{2.538}{0.75}](https://tex.z-dn.net/?f=%5Cfrac%7B2.538%7D%7B0.75%7D)
= 3.384
v = 3.38 m
The person's image is 3.38 m tall.
Answer:
29274.93096 m/s
![2.73966\times 10^{33}\ J](https://tex.z-dn.net/?f=2.73966%5Ctimes%2010%5E%7B33%7D%5C%20J)
![-5.39323\times 10^{33}\ J](https://tex.z-dn.net/?f=-5.39323%5Ctimes%2010%5E%7B33%7D%5C%20J)
![2.56249\times 10^{33}\ J](https://tex.z-dn.net/?f=2.56249%5Ctimes%2010%5E%7B33%7D%5C%20J)
![-5.21594\times 10^{33}](https://tex.z-dn.net/?f=-5.21594%5Ctimes%2010%5E%7B33%7D)
Explanation:
= Distance at perihelion = ![1.471\times 10^{11}\ m](https://tex.z-dn.net/?f=1.471%5Ctimes%2010%5E%7B11%7D%5C%20m)
= Distance at aphelion = ![1.521\times 10^{11}\ m](https://tex.z-dn.net/?f=1.521%5Ctimes%2010%5E%7B11%7D%5C%20m)
= Velocity at perihelion = ![3.027\times 10^{4}\ m/s](https://tex.z-dn.net/?f=3.027%5Ctimes%2010%5E%7B4%7D%5C%20m%2Fs)
= Velocity at aphelion
m = Mass of the Earth = 5.98 × 10²⁴ kg
M = Mass of Sun = ![1.9889\times 10^{30}\ kg](https://tex.z-dn.net/?f=1.9889%5Ctimes%2010%5E%7B30%7D%5C%20kg)
Here, the angular momentum is conserved
![L_p=L_a\\\Rightarrow r_pv_p=r_av_a\\\Rightarrow v_a=\frac{r_pv_p}{r_a}\\\Rightarrow v_a=\frac{1.471\times 10^{11}\times 3.027\times 10^{4}}{1.521\times 10^{11}}\\\Rightarrow v_a=29274.93096\ m/s](https://tex.z-dn.net/?f=L_p%3DL_a%5C%5C%5CRightarrow%20r_pv_p%3Dr_av_a%5C%5C%5CRightarrow%20v_a%3D%5Cfrac%7Br_pv_p%7D%7Br_a%7D%5C%5C%5CRightarrow%20v_a%3D%5Cfrac%7B1.471%5Ctimes%2010%5E%7B11%7D%5Ctimes%203.027%5Ctimes%2010%5E%7B4%7D%7D%7B1.521%5Ctimes%2010%5E%7B11%7D%7D%5C%5C%5CRightarrow%20v_a%3D29274.93096%5C%20m%2Fs)
Earth's orbital speed at aphelion is 29274.93096 m/s
Kinetic energy is given by
![K=\frac{1}{2}mv_p^2\\\Rightarrow K=\frac{1}{2}\times 5.98\times 10^{24}(3.027\times 10^{4})^2\\\Rightarrow K=2.73966\times 10^{33}\ J](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7Dmv_p%5E2%5C%5C%5CRightarrow%20K%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%205.98%5Ctimes%2010%5E%7B24%7D%283.027%5Ctimes%2010%5E%7B4%7D%29%5E2%5C%5C%5CRightarrow%20K%3D2.73966%5Ctimes%2010%5E%7B33%7D%5C%20J)
Kinetic energy at perihelion is ![2.73966\times 10^{33}\ J](https://tex.z-dn.net/?f=2.73966%5Ctimes%2010%5E%7B33%7D%5C%20J)
Potential energy is given by
![P=-\frac{GMm}{r_p}\\\Rightarrow P=-\frac{6.67\times 10^{-11}\times 1.989\times 10^{30}\times 5.98\times 10^{24}}{1.471\times 10^{11}}\\\Rightarrow P=-5.39323\times 10^{33}](https://tex.z-dn.net/?f=P%3D-%5Cfrac%7BGMm%7D%7Br_p%7D%5C%5C%5CRightarrow%20P%3D-%5Cfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%201.989%5Ctimes%2010%5E%7B30%7D%5Ctimes%205.98%5Ctimes%2010%5E%7B24%7D%7D%7B1.471%5Ctimes%20%2010%5E%7B11%7D%7D%5C%5C%5CRightarrow%20P%3D-5.39323%5Ctimes%2010%5E%7B33%7D)
Potential energy at perihelion is ![-5.39323\times 10^{33}\ J](https://tex.z-dn.net/?f=-5.39323%5Ctimes%2010%5E%7B33%7D%5C%20J)
![K=\frac{1}{2}mv_a^2\\\Rightarrow K=\frac{1}{2}\times 5.98\times 10^{24}(29274.93096)^2\\\Rightarrow K=2.56249\times 10^{33}\ J](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7Dmv_a%5E2%5C%5C%5CRightarrow%20K%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%205.98%5Ctimes%2010%5E%7B24%7D%2829274.93096%29%5E2%5C%5C%5CRightarrow%20K%3D2.56249%5Ctimes%2010%5E%7B33%7D%5C%20J)
Kinetic energy at aphelion is ![2.56249\times 10^{33}\ J](https://tex.z-dn.net/?f=2.56249%5Ctimes%2010%5E%7B33%7D%5C%20J)
Potential energy is given by
![P=-\frac{GMm}{r_a}\\\Rightarrow P=-\frac{6.67\times 10^{-11}\times 1.989\times 10^{30}\times 5.98\times 10^{24}}{1.521\times 10^{11}}\\\Rightarrow P=-5.21594\times 10^{33}](https://tex.z-dn.net/?f=P%3D-%5Cfrac%7BGMm%7D%7Br_a%7D%5C%5C%5CRightarrow%20P%3D-%5Cfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%201.989%5Ctimes%2010%5E%7B30%7D%5Ctimes%205.98%5Ctimes%2010%5E%7B24%7D%7D%7B1.521%5Ctimes%2010%5E%7B11%7D%7D%5C%5C%5CRightarrow%20P%3D-5.21594%5Ctimes%2010%5E%7B33%7D)
Potential energy at aphelion is ![-5.21594\times 10^{33}\ J](https://tex.z-dn.net/?f=-5.21594%5Ctimes%2010%5E%7B33%7D%5C%20J)
If you think about it, irregular galaxies dont really have a describable shape, as you can tell by the name. So B.