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valentinak56 [21]
3 years ago
10

A ball falling though the air has ?

Physics
1 answer:
Sav [38]3 years ago
3 0
It has both potential and kinetic energy.

Since the ball is falling through the air its going to keep going faster and faster since gravity is pulling it downward so its not going to stop unless it hits something or someone catches it.
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The number of employees for a certain company has been decreasing each year by 4%. If the company currently has 650 employees an
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A piece of wood on top of an ocean wave stays in the same location, only moving up and down as the wave passes. It is energy tha
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Hey

Yes, this is true.

As some people have it wrong, waves in the water (ocean) are not waves of moving water, rather the wave is moving through the water. A wave is a disturbance of a medium not the meduim moving.

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Use absolute dating in a sentence
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scientists will use absolute dating to find how old a fossil exactly is.

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Read 2 more answers
Three charges, q1 = +2.06 x 10-9 C, q2 = -3.27 x 10-9 C, and q3 = +1.05 x 10-9 C, are located on the x-axis at x1 = 0, x2 = 10.0
lisov135 [29]

Answer:

The resultant force on charge 3 is Fr= -2,11665 * 10^(-7)

Explanation:

Step 1: First place the three charges along a horizontal axis. The first positive charge will be at point x=0, the second negative charge at point x=10 and the third positive charge at point x=20. Everything is indicated in the attached graph.

Step 2: I must calculate the magnitude of the forces acting on the third charge.

F13: Force exerted by charge 1 on charge 3.

F23: Force exerted by charge 2 on charge 3.

K: Constant of Coulomb's law.

d13: distance from charge 1 to charge 3.

d23: distance from charge 2 to charge 3

Fr: Resulting force.

q1=+2.06 x 10-9 C

q2= -3.27 x 10-9 C

q3= +1.05 x 10-9 C

K=9-10^9 N-m^2/C^2

d13= 0,20 m

d23= 0,10 m

F13= K * (q1 * q3)/(d13)^2

F13=9,7335*10^(-8) N

F23=K * (q2 * q3)/(d23)^2

F23= -3,09 * 10^(-7)

Step 3: We calculate the resultant force on charge 3.

Fr=F13+F23= -2,11665 * 10^(-7)

3 0
3 years ago
Guiana dolphins are one of the few mammals able to detect electric fields. In a test of sensitivity, a dolphin was exposed to th
iren [92.7K]

Answer:

0.05 V/m

Explanation:

V = Potential difference that is possible for the dolphin to detect = 0.5 mV

d = Distance between electrodes = 1 cm

Electric field strength is given by

E=\dfrac{V}{d}

\Rightarrow E=\dfrac{0.5\times 10^{-3}}{1\times 10^{-2}}

\Rightarrow E=0.05\ V/m

The corresponding electric field strength is 0.05 V/m

8 0
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