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2 years ago

Would you expect an organic compound to be soluble in water why

1 answer:

3 0

Answer: All organic compound depends on H-bonding with water. more stronger H-bonding with water more will be soluble.

Explanation:

1. It depends primarily upon the function groups of that compound. It also depends on the size of the compound.

2. some organic compound which soluble in water for example: alcohols, ethers, carboxylic acids. Because of the functional groups attached to the organic structure (the C-H backbone) are what effect the solubilities.Like carboxylic acids and alcohols form hydrogen bonds with the water, helping to solubilize it.

3. Take alcohols for example: methanol, ethanol, and isopropanol are all completely soluble in water. By the time you get to butanol and some of the larger alcohols, including those with more complex structures, they tend to be less soluble.

You might be interested in

How many mols are present in the a sample of silver nitrate which has<br> 5.3x10^24 molecules.

Westkost [7]

Answer: 5.3 x 10^24 formula units of silver nitrate is equivalent to 8.8 moles of silver nitrate. Silver nitrate is an ionic compound, therefore, its representative particle is called a "formula unit" instead of molecule. For every mole of a substance, we know that there are 6.022 x 10^23 representative units of that substance. The amount of particles in one mole of substance is called Avogadro's number.

Further Explanation:

We can convert from number of representative particles to moles using the formula:

$\boxed {no. \ of \ moles \ = \ ( given \ no. \ of \ particles) \ (\frac{1 \ mole}{\ 6.022 \ x 10^{23} particles})}$

For this problem, we can calculate the number of moles by plugging in the given values to the equation above,

$no. \ of \ moles \ = (5.3 \ x \ 10^{24} \ formula \ units \ AgNO_{3}) \ (\frac{1 \ mole \ AgNO_{3}}{6.022 \ x 10^{23} \ formula \ units AgNO_{3}}) \\\\\boxed {no. \ of moles \ AgNO_{3} \ = \ 8.8 \ moles}$

Learn More

Learn more about representative particles brainly.com/question/8969313
Learn more about Avogadro's number brainly.com/question/229300
Learn more about mole conversions brainly.com/question/1370888

Keywords: moles conversion, Avogadro's number

5 0

2 years ago

What is the mass of 2N at 0.2829 atm 1.35 L and 25°C

maria [59]

<h3>Answer:</h3>

0.437 g

<h3>Explanation:</h3>

From the question we have;

Pressure of the gas as 0.2829

Volume of the gas as 1.35 L

Temperature of the gas as 25°C

But, K = °C + 273.15

Therefore, temperature of the gas is equivalent to 298.15 K

We are required to calculate the mass of the gas

<h3>Step 1: Number of moles of the gas </h3>

Using the ideal gas equation, PV = nRT , we can determine the number of moles.

R is the ideal gas constant, 0.082057 L.atm/mol.K

Therefore, rearranging the formula;

n = PV ÷ RT

= (0.2829 atm × 1.35 L) ÷ (0.082057 × 298.15 K)

= 0.0156 mole

Therefore, the number of moles of the gas is 0.0156 mole

We know that mass of a compound is the product of moles and the molar mass.

Mass = Moles × Molar mass

Molar mass of the gas is 28.0134 g/mol

Therefore;

= 0.0156 mole × 28.0134 g/mol

= 0.437 g

Thus, the mass of the gas is 0.437 g

5 0

2 years ago

The activation energies are 45. 3 kj mol^-1 for k1 and 69. 8 kj mo1-1 for k2. If the rate constants are equal at 320 k, at what

Katyanochek1 [597]

At temperature 298K, the value of k1/k2 will equal to 2.00

According to Arrhenius's equation

Sometimes the Arrhenius equation is written as k = Ae- $^{E/RT}$ , where k is the rate of the chemical reaction, A is a constant that varies depending on the chemicals involved, E is the activation energy, and R is the universal gas constant, and T is the temperature.