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umka21 [38]
3 years ago
13

What is the mass of 4.32 mol GaI3? 455 g 1,230 g 1,720 g 1,950 g

Chemistry
1 answer:
denis23 [38]3 years ago
8 0

Answer:

D. 1,950 g

Explanation:

I completed the test and it is the correct answer!

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solmaris [256]

Answer:

D. bromine

Explanation:

Highest electronegativity in the period has element closest to the *A group

K Ca Cu Br

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3 years ago
what would the molarity of a solution be if you took 10 mL of a 13M stock solution and made a 300 mL solution?
nignag [31]

Answer:

0.43M

Explanation:

8 0
3 years ago
What happens to the rate of diffusion when pressure of gas is increased?​
luda_lava [24]

In general, the diffusion coefficient is inversely proportional to pressure. This is also an observed fact: gas production rates from coal seams tend to increase as the reservoir pressure goes down.

5 0
2 years ago
An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 113 amu and 115 amu, with natural abunda
DENIUS [597]

Answer: Its average atomic mass is 114.9 amu

Explanation:

Mass of isotope 1 = 113 amu

% abundance of isotope 1 = 5% = \frac{5}{100}=0.05

Mass of isotope 2 = 115 amu

% abundance of isotope 2 = 95% = \frac{95}{100}=0.95

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(113\times 0.05)+(115\times 0.95)]

A=114.9amu

Thus its average atomic mass is 114.9 amu

5 0
3 years ago
Determine the LIMITING reactant in the following balanced equation:
padilas [110]

Answer:

KBr is limiting reactant.

Explanation:

Given data:

Mass of  KBr =4g

Mass of Cl₂ = 6 g

Limiting reactant = ?

Solution:

Chemical equation:

2KBr + Cl₂      →    2KCl + Br₂

Number of moles of KBr:

Number of moles = mass/molar mass

Number of moles = 4 g/ 119 gmol

Number of moles = 0.03 mol

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 6 g/ 70 gmol

Number of moles = 0.09 mol

Now we will compare the moles of reactant with product.

              KBr            :            KCl

                2              :              2

            0.03            :            0.03

             KBr            :              Br₂

                2             :               1

             0.03           :          1/2×0.03= 0.015

               Cl₂             :            KCl

                 1              :              2

            0.09            :           2/1×0.09 = 0.18

               Cl₂             :              Br₂

                1              :               1

             0.09           :            0.09

Less number of moles of product are formed by the KBr thus it will act as limiting reactant while Cl₂  is present in excess.

5 0
3 years ago
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