It is the answer of 10 51
Plasma or white blood cells
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The enthalpy change, ΔH for the following reaction 
is -452.76 kJ.
<h3>What is enthalpy change, ΔH, of a reaction?</h3>
The enthalpy change of a reaction is the heat changes that occurs when a reaction proceeds to formation of products.
- Enthalpy change, ΔH = ΔH of products - ΔH of reactants
The equation of the reaction is given below
Therefore, the enthalpy change, ΔH for the following reaction is -452.76 kJ.
Learn more about enthalpy change at: brainly.com/question/14047927
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Answer:
what language is this is this english?
Answer:
1.49 × 10⁹ years
Explanation:
Step 1: Calculate the rate constant (k) for the nuclear decay of U-235
The decay follows first-order kinetics with a half-life (t1/2) of 703 × 10⁶ years. We can calculate "k" using the following expression.
k = ln2/ t1/2 = ln2 / 703 × 10⁶ y = 9.86 × 10⁻¹⁰ y⁻¹
Step 2: Calculate the time elapsed (t) so that the final amount ([U]) is 23.0% of the initial amount ([U]₀)
For first order kinetics, we will use the following expression.
ln ([U]/[U]₀) = -k × t
ln (0.230[U]₀/[U]₀) = -9.86 × 10⁻¹⁰ y⁻¹ × t
ln 0.230 = -9.86 × 10⁻¹⁰ y⁻¹ × t
t = 1.49 × 10⁹ y
