All categories

3 years ago

Will baby oil and water form a solution

Chemistry

2 answers:

Alina [70]3 years ago

5 0

They will not form a solution because one is more dense than the other.

Arlecino [84]3 years ago

3 0

Water has a greater density than oil. Baby oil and water wont form a solution.

You might be interested in

Match the scientist with their achievement:

Tju [1.3M]

Answer:

Frederich Miescher- first person to isolate DNA and RNA

Frederick Griffith- first to demonstrate horizontal transmission of dna using bacteria

Gregor Mendel- documented and demonstrated inheritance patterns

Thomas Hunt Morgan- identified chromosomes as the structures responsible for inheritance

Joachim Hammerling- demonstrated that the hereditary information of of eukaryotes is contained within the nucleus

Alfred Hershey and Martha Chase- demonstrated that dna not protein was the molecule responsible for hereditary

George Beadle and Edward Tatum- used mutants to show the relationship between DNA and proteins

Albrecht Kossel- characterized the structure of adenine, guanine, cytosine, thymine, and uracil

Explanation:

Hope this helps! Pls give brainliest!

5 0

2 years ago

Pure metals tend to be weaker and more reactive than an alloy which is a

Alex17521 [72]

Alloys are supposed to give greater strength to metals, which is why gold is mixed with others to make it harder. They have greater strength and are more resistant to erosion.

5 0

3 years ago

Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h

bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

We know that,

The relation between the $C_p\text{ and }C_v$ for an ideal gas are :

$C_p-C_v=R$

As we are given :

$C_p=28.253J/K.mole$

$28.253J/K.mole-C_v=8.314J/K.mole$

$C_v=19.939J/K.mole$

Now we have to calculate the entropy change of the gas.

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

$\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J$

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. $(w=-pdV)$

(C) Heat during the process will be,

$q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J$

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0

3 years ago

A gas occupies a volume of 31.0 ml at 19.0°C. If the gas temperature rises to 38.0°C at constant pressure. Calculate the new vol

Alik [6]

Answer:

The correct answer is 0.0033 L (33.0 mL)

Explanation:

We uses the Charles's law which describes the changes in the volume (V) of a gas and its temperature in Kelvin (T) at constant pressure. The mathematical expression is the following:

V₁/T₁ = V₂/T₂

We have the following data:

V₁= 31.0 mL = 0.0031 L

T₁= 19.0°C = 292 K

T₂= 38.0°C = 311 K

V₂= ?

We calculate V₂ from the mathematical expression, as follows:

V₂= V₁/T₁ x T₂ = 0.0031 L/(292 K) x 311 K = 0.0033 L

5 0

2 years ago

Why are the densities of corn syrup and gasoline expressed as a range of values

balu736 [363]

because gasoline changes volume as a function of temperature or because there are different grades of gasoline or because the values are given in different units of measure .

7 0

2 years ago