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stiks02 [169]
2 years ago
11

A car manufacturer needs to assemble the maximum number of cars using the following equation: 1 body frame + 4 wheels + 2 headli

ghts + 2 brakes + 1 engine It has 48 body frames, 64 headlights, 80 wheels, 60 brakes and 30 engines. What is the limiting reactant in this case?
Chemistry
1 answer:
larisa [96]2 years ago
8 0

The wheels will be completely used up and  it is the limiting reactant in this case.

<h3>What is a limiting reactant?</h3>

The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops.

  • 60 breaks will be used for 30 engines and 30 body frame
  • 80 wheels will be used for 20 engines and 20 body frame
  • 64 headlights will be used for 32 engines and 32 body frame

The wheels will be completely used up and  it is the limiting reactant in this case.

Learn more about limiting reactants here: brainly.com/question/14222359

#SPJ1

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As you move across the period on the periodic table what pattern can be described about the electron configurations?
xeze [42]

Answer:

Elements in the same period have same number of electronic shell and electron is increased by one in every coming element with in same electronic shell.

Explanation:

Consider the second period of periodic table. This period consist of eight elements lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine and neon.

Electronic configuration of lithium:

Li₃ = [He] 2s¹

Electronic configuration of beryllium:

Be₄ = [He] 2s²

Electronic configuration of boron:

B₅ = [He] 2s² 2p¹

Electronic configuration of carbon:

C₆ = [He] 2s² 2p²

Electronic configuration of nitrogen:

N₇ = [He] 2s² 2p³

Electronic configuration of oxygen:

O₈ = [He] 2s² 2p⁴

Electronic configuration of fluorine:

F₉ = [He] 2s² 2p⁵

Electronic configuration of neon:

Ne₁₀ = [He] 2s² 2p⁶

All these elements present in same period having same electronic shell and number of electron increased by 1.

4 0
3 years ago
Im hvaing a hard time getting the right answer
Tanya [424]

Answer:

V=23.9mL

Explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

n=2.49g*\frac{1mol}{125.55 g}=0.0198mol

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

M=\frac{n}{V}\\\\V=\frac{n}{M}

By plugging in the moles and molarity, we obtain:

V=\frac{0.0198mol}{0.830mol/L}=0.0239L

Which in mL is:

V=0.0239L*\frac{1000mL}{1L}\\\\V=23.9mL

Best regards!

6 0
3 years ago
What is the half-life in minutes of a compound if 75.0 percent of a given sample decomposes in 40.0 minutes? Assume first-order
yaroslaw [1]

Answer:

See below

Explanation:

.75 = 1/2^(40/h)      

log .75 / ( log 1/2) = 40 / h

<u>h = half life =   96.37683 min</u>

8 0
2 years ago
1.2 L sample of gas is determined to contain 0.5 moles of nitrogen. At the same temperature and pressure, how many moles of gas
hram777 [196]

A 20 L sample of the gas contains 8.3 mol N₂.

According to <em>Avogadro’s Law,</em> if <em>p</em> and <em>T</em> are constant

<em>V</em>₂/<em>V</em>₁ = <em>n</em>₂/<em>n</em>₁

<em>n</em>₂ = <em>n</em>₁ × <em>V</em>₂/<em>V</em>₁

___________

<em>n</em>₁ = 0.5 mol; <em>V</em>₁ = 1.2 L

<em>n</em>₂ = ?;           <em>V</em>₂ = 20 L

∴<em>n</em>₂ = 0.5 mol × (20 L/1.2 L) = 8.3 mol

4 0
3 years ago
Why are leaves different colors?
Marina86 [1]
<span>Why are leaves different colors?</span><span>
The chlorophyll breaks down</span>
6 0
3 years ago
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