Answer:
C. Precipitation of white bismuth hydroxide.
Explanation:
When aqueous ammonia is added to a solution that has Bi3+ and CU2+ cations, what we would have as a chemical result is the precipitation of white Bismuth hydroxide.
The chemical reaction for this can be written as,
Bi3+ + 2NH3 + 3H2O ⇌ Bi(OH)3(s) + 3NH4
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The spoon should be connected to the negative terminal of the battery. The other electrode should be made of silver.
The balance chemical equation is
2N2 + O2 ---> 2N2O.
We can solve how many moles of nitrous oxide gas from 1.65 moles of nitrogen gas. The balance equation is a critical information to answer this problem since it gives the ratio of <span>nitrous oxide gas produced</span> to the nitrogen used. 2 moles of nitrous oxide gas is produced from 2 moles of nitrogen gas is used. Hence there is 1.65 moles of nitrous oxide gas produced.
Answer:
72.2 ml
Explanation:
The neutralization equation between HBr (acid) and NaOH (base) is the following:
HBr(aq) + NaOH(aq) → NaBr(aq) + H₂O(l)
We can see that 1 mol of HBr reacts with 1 mol of NaOH. At the equivalence point, the total number of moles of HBr reacts with the total number of moles of NaOH. The number of moles can be calculated as the product between the molarity (M, in mol/L) and the volume (V). So, we can equal the quantities of acid and base, as follows:
moles HBr = moles NaOH
M(HBr) x V(HBr) = M(NaOH) x V(NaOH)
Now, we calculate the volume of NaOH with the data:
V(NaOH)= M(HBr) x V(HBr)/M(NaOH)
= (2.60 mol/L x 50.0 ml)/(1.80 mol/L)
=72.2 ml