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zubka84 [21]
3 years ago
11

If the hydroxide ion [OH-] concentration of an aqueous solution is 1 x 10 -3 M, what is the [H+] in the solution? Is the solutio

n acidic, basic, or neutral?
Chemistry
1 answer:
Dominik [7]3 years ago
4 0

Answer:

pH = 11, The solution is Basic.

Explanation:

We know that;

[OH-] [H+] = 1 × 10^-14

we are given; [OH-] as 1 x 10^ -3 M

Therefore, we can get the [H+] by;

[H+] = 1 × 10^-14/[OH-]

       = 1 × 10^-14 M/1 x 10^ -3 M

       =  1 × 10^-11 M

But; pH = - log [H+]

Thus,

pH = - log (1 ×10^-11 M)

     =  11

pH = 11, which means the solution is basic.

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Which sample contains more atoms:<br> 3.89 g of nickel or 6.61 g of silver?<br> Defend your answer.
Alenkinab [10]
Nickel contains more atoms
3 0
2 years ago
29.5 g of mercury is heated from 32°C to 161°C, and absorbs 499.2 joules of heat in the process. Calculate the specific heat cap
Finger [1]

Answer:

c = 0.13 j/ g.°C

Explanation:

Given data:

Mass of mercury = 29.5 g

Initial temperature = 32°C

Final temperature = 161°C

Heat absorbed = 499.2 j

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m.c. ΔT

ΔT  = T2 - T1

ΔT  = 161°C - 32°C

ΔT  = 129 °C

Q = m.c. ΔT

c = Q / m. ΔT

c = 499.2 j / 29.5 g. 129 °C

c =  499.2 j / 3805.5 g. °C

c = 0.13 j/ g.°C

5 0
3 years ago
Please help me with this question please!!!
Deffense [45]

Answer:

A

Explanation:

I looked up aromatic hydrocarbon and this one looks like a replica of benzene

3 0
3 years ago
What is the concentration of hydronium ion in a 0.121 M HCl solution?
kogti [31]

Answer:

C) 0.121 M

Explanation:

HCl + H₂O = H₃O⁺ + OH⁻

.121M              .121M

HCl is a strong acid . It will dissociate almost 100 % so the concentration of acid and hydronium ion formed will be equal . It is to be noted that hydronium ion is formed due to association of H⁺ and H₂O . H⁺ is formed due to ionisation of HCl .

So concentrtion of hydronium ion ( H₃O⁺ ) will be .121 M.

7 0
3 years ago
If the half life of a radioactive isotope is 5000 years, how much of the radioactive isotope in a specimen will be left after 10
marissa [1.9K]
Half life is the time taken by a radioactive isotope to decay by half its original mass. In this case, the halflife of the radioactive isotope is 5000 years. 
Initially the mass is 100 %; thus the mass that will be left will be given by;
New mass = Original mass × (1/2)^n where n is the number of half lives; 
  n = 10000/5000 = 2
New mass = 100% ×(1/2)^2
                 = 100 % × 1/4 
                 = 25%
Therefore; the mass left after 10000 years is 25% or 1/4 of the original mass.
5 0
3 years ago
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