Explanation:
Let h is the height of the plane above ground. x is the horizontal distance between the ground and the airport. Let s(t) is the distance between the plane and the airport. So,
...........(1)
Given, h = 4, x = 40 and s(t) = -20 mph
Differentiate equation (1) wrt t


When x = 40, 



So, the speed of the airplane is 241.14 m/s. Hence, this is the required solution.
So first things first its c. because when two plates collide it causes a earthquake so u can rule those out and of course no not volcano so that's it u only have c left as your answer choice.
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Answer: 0.1 m/s
Explanation:
Use formula,
v = f * w where, v is speed, f is frequency and w is wavelength.
Now,
v = 2 * 5 * 10 ^ -2 ( Remember to convert all the units to SI units. Here 5 cm becomes 5 * 10 ^ -2 m. )
v = 0.1 m/s.
Answer:
0.625 c
Explanation:
Relative speed of a body may be defined as the speed of one body with respect to some other or the speed of one body in comparison to the speed of second body.
In the context,
The relative speed of body 2 with respect to body 1 can be expressed as :

Speed of rocket 1 with respect to rocket 2 :



Therefore, the speed of rocket 1 according to an observer on rocket 2 is 0.625 c
K = C + 273, so 27°C = 27+273 = 300 K
1 dg = 100 mg, so 20 dg = 20×100 = 2,000 mg