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3 years ago

10

A wave with a fequency of 12 hz has a wavelength of 1.5 meter. at what speed will this wave travel?

1 answer:

avanturin [10]3 years ago

5 0

V used to denote speed of the wave

Is determined by the product of the wave’s frequency and wavelength.

The number of times a wave oscillates or repeats again and again multiplied by the distance.

V = 12 • 1.5 = 12 • 3/2 = 18 m/s

The speed of the wave is 18 m/s.

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Scorpion4ik [409]

<u>Given</u><u> </u><u>:</u><u>-</u>

A 20kg block at an angle 53⁰ in an inclined plane is released from rest .
$\mu_s = 0.3 \ \& \ \mu_k = 0.2$

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

Would the block move ?
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<u>Solution</u><u> </u><u>:</u><u>-</u>

For figure refer to attachment .

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Substitute ,

$\longrightarrow \theta_{repose}= tan^{-1}( 0.2)$

Solve ,

$\longrightarrow\underline{\underline{\theta_{repose}= 16.6^o }}$

Hence ,

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And the net force will be ,

$\longrightarrow F_n = mgsin53^o - \mu_k N$

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$\longrightarrow ma_n = mgsin53^o - \mu_k mgcos53^o$

Take m as common,

$\longrightarrow\cancel{m }(a_n) = \cancel{m}( gsin53^o - \mu gcos53^o)$

Simplify ,

$\longrightarrow a_n = gsin53^o - \mu_k g cos53^o$

Substitute the values of sin , cos and g ,

$\longrightarrow a_n = 10( 0.79 - 0.2 (0.6))$

Simplify ,

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Now using the <u>Third </u><u>equation</u><u> </u><u>of</u><u> motion</u><u> </u>namely,

$\longrightarrow2as = v^2-u^2$

Substituting the respective values,

$\longrightarrow2(6.7)(5) = v^2-(0)^2$

Simplify and solve for v ,

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<u>Hence</u><u> the</u><u> </u><u>velocity</u><u> after</u><u> </u><u>covering</u><u> </u><u>5</u><u>m</u><u> </u><u>is </u><u>8</u><u>.</u><u>1</u><u>8</u><u> </u><u>m/</u><u>s </u><u>.</u>

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Answer:

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