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Luba_88 [7]
3 years ago
10

A wave with a fequency of 12 hz has a wavelength of 1.5 meter. at what speed will this wave travel?

Physics
1 answer:
avanturin [10]3 years ago
5 0
V used to denote speed of the wave

Is determined by the product of the wave’s frequency and wavelength.

The number of times a wave oscillates or repeats again and again multiplied by the distance.

V = 12 • 1.5 = 12 • 3/2 = 18 m/s

The speed of the wave is 18 m/s.
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If the change in velocity increases what happens to the acceleration during the same time period?
viva [34]

Answer:

Acceleration increases

Explanation:

3 0
3 years ago
A girl dribbling a basketball is running a court that is 100 m in length. It takes her 4.2 seconds to reach the end of the court
Travka [436]

Divide the distance traveled by the time it took:

(100 m) / (4.2 s) ≈ 23.8 m/s

6 0
3 years ago
A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete
lapo4ka [179]

Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ F_x=mgSin \theta=ma

⇒ a_x=gSin \theta

       =9.8 \ Sin35^{\circ}

       =5.62 \ m/s^2

(b)

If friction present,

⇒ F_x=mgCos \theta

⇒ F_x=mgSin \theta-\mu_r mgCos \theta

⇒ a=gSin \theta-\mu_rgCos \theta

      =9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}

      =5.46 \ m/s^2

8 0
3 years ago
Light is polarized by using:
maxonik [38]

Answer:

Polaroid fliter

Explanation:

light can be polarized by using Polaroid filters

Polaroid fliter are made of special material that is capable of blocking one of the two planes of vibration of an electromagnetic wave

hope this is useful--(have a good day)

8 0
3 years ago
An avant-garde composer wants to use the Doppler effect in his new opera. As the soprano sings, he wants a large bat to fly towa
Allisa [31]

Answer:

     v’= 9.74 m / s

Explanation:

The Doppler effect is due to the relative movement of the sound source and the receiver of the sound, in this case we must perform the exercise in two steps, the first to find the frequency that the bat hears and then the frequency that the audience hears that also It is sitting.

Frequency shift heard by the murciela, in case the source is still and the observer (bat) moves closer

        f₁ ’= f₀ (v + v₀)/v

         

Frequency shift emitted by the speaker in the bat, in this case the source is moving away from the observer (public sitting) that is at rest

         f₂’= f₁’ v/(v - vs)

           

Note that in this case the bat is observant in one case and emitter in the other, called its velocity v’

            v’= vo = vs

Let's replace

           f₂’= f₀   (v + v’)/v   v/(v -v ’)

           f₂’= f₀   (v + v’) / (v -v ’)

           (v –v’ ) f₂’ / f₀ = v + v ’

           v’ (1+ f₂’ /f₀) = v (f₂’/fo - 1)

           v’ (1 + 1.059) = 340 (1.059 - 1)

           v’= 20.06 / 2.059

           v’= 9.74 m / s

6 0
3 years ago
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