Explanation:
the answer and explanation is in the picture
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I think cathode should be silver or gold
you can use silver nitrate solution or mercury nitrate solution
Answer:
The activation energy is 164.02 kJ/mol
Explanation:
Log (k2/k1) = Ea/2.303R × [1/T1 - 1/T2]
k1 = 8.9×10^-4 s^-1
k2 = 9.83×10^-3 s^-1
R = 8.314 J/mol.K
T1 = 540 K
T2 = 578 K
Log (9.83×10^-3/8.9×10^-4) = Ea/2.303×8.314 × [1/540 - 1/578]
1.043 = 6.359×10^-6Ea
Ea = 1.043/6.359×10^-6 = 164020 J/mol = 164020/1000 = 164.02 kJ/mol
Answer:
D. 4.281 x 10⁻¹⁹ Joules.
Explanation:
- To get the change in energy, we can use the relation:
<em>E = (hc)/λ</em>
where,
E is the energy of the atom.
h is Planck’s constant = 6.626 x 10⁻³⁴ J.s.
c is the speed of light = 2.998 x 10⁸ m/s.
λ is the wavelength of photon = 4.64 x 10⁻⁷ m.
<em>∴ E = (hc)/λ</em> = (6.626 x 10⁻³⁴ J.s)(2.998 x 10⁸ m/s)/(4.64 x 10⁻⁷ m) = <em>4.281 x 10⁻¹⁹ J.</em>
A is the answer to this question. Thank you.
