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frez [133]
2 years ago
11

What type(s) of intermolecular forces are expected between ch3ch2ch2ch2oh molecules?

Chemistry
2 answers:
Alexxx [7]2 years ago
8 0

Answer:

1. Hydrogen bonding

2. Dipole dipole interaction

3. London dispersion force

Explanation:

Intermolecular forces refers to the force of attraction or force of repulsion between two molecules of same or other type.

In this case three types of Intermolecular forces acting:

1. Hydrogen bonding between O and H atom of different molecules.

2. Dipole dipole interaction between C and O atom because of great electronegative difference.

3. London dispersion force it is between two -CH_3 group of different molecules. It is also known as induced dipole force.

Hence, this is the required solution.  

12345 [234]2 years ago
5 0

Answer : Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.

Explanation :

The given molecule is CH_3CH_2CH_2CH_2OH.

Three types of inter-molecular forces are present in this molecule which are Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.

  • Hydrogen-bonding : when the partial positive end of hydrogen is bonded with the partial negative end of another molecule like, oxygen, nitrogen, etc.
  • Dipole-dipole attraction : When the partial positively charged part of the molecule is interact with the partial negatively charged part of the molecule. For example : In case of HCl.
  • London-dispersion force : This force is present in all type of molecule whether it is a polar or non-polar, ionic or covalent. For example : In case of Br-Br , F-F, etc

Hydrogen-bonding is present between the oxygen and hydrogen molecule.

Dipole-dipole forces is present between the carbon and oxygen molecule.

London-dispersion forces is present between the carbon and carbon molecule.

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2 years ago
The student is now told that the four solids, in no particular order, are aluminum chloride (AlCl3), sugar (C6H12O6), benzoic ac
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Answer:

AlCl₃, NaBr, C₆H₅COOH, C₆H₁₂O₆.

Explanation:

The more ions in solution, the greater the conductivity of a solution because these charged particles can carry electrons in the solution.

In the first place, when AlCl₃ dissolves in water it produces 4 ions:

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If the solution is 0.20M in AlCl₃, it will be 4 x 0.20M = 0.80M in ions.

Secondly, NaBr is a strong electrolyte (<em>complete ionization</em>) so it produces 2 moles of ions per each mole of NaBr dissolved:

NaBr(aq) ⇄ Na⁺(aq) + Br⁻(aq)

If the solution is 0.20M in NaBr, it will be 2 x 0.20M = 0.40M in ions.

Then, benzoic acid is a weak electrolyte (<em>partial ionization</em>) so it will produce <em>less than</em> 2 moles of ions per each mole of benzoic acid dissolved:

C₆H₅COOH(aq) ⇄ C₆H₅COO⁻(aq) + H⁺(aq)

If the solution is 0.20M in benzoic acid, the solution will be far below 0.40M in ions.

Finally, sugar has only nonpolar covalent bonds so it will produce no ions in solution, thus being a poor electricity conductor.

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