Answer: a. 0.8 tons p. month.
Explanation:
Given: Total nuclear waste = 60,000 metric tons
Time take = 60 years = 12 x 60 months [ 1 year = 12 months]
= 720 months
Total nuclear power plants = 104
Now , Average waste produced by each plant = 

Hence, 0.8 tons p. month is produced by each plant.
So, option a. is correct.
Rutherford was one of the early scientists who worked on the atomic model. Before his discovery of the nucleus, the widely accepted theory was J.J Thomson's Plum Pudding Model. In this model, all the protons, electrons and neutrons are in the nucleus. But the electrons are more in number such that the electrons act as the 'pudding' and the proton and nucleus the 'plum'. This was Rutherford's hypothesis in his gold foil experiment. In order to test the Plum Pudding model, he hypothesized that when a beam of light is aimed at the atom, it would not diffract because the charges in the nucleus are well-distributed. However, his experiment disproved Thomson's model. Some light indeed passed through but a few was diffracted back to the source. He concluded that this was because there is a dense mass inside the atom called nucleus. Thus, from there on, he proposed the model that the electrons are orbiting around the nucleus.
the reagents necessary to convert alcohol to ketone
which involves oxidation of alcohols.
<h3>
What is oxidation of alcohols?</h3>
- Alcohol oxidation is a significant organic chemistry process. Secondary alcohols can be oxidized to produce ketones, while primary alcohols can be oxidized to produce aldehydes and carboxylic acids.
- In contrast, tertiary alcohols cannot be oxidized without the C-C bonds in the molecule being broken.
- In order to cause primary alcohols to oxidize into aldehydes
(dichromate)
/pyridine (Collins reagent)- Chromium pyridinium compound (PCC)
- Dichromate of pyridinium (PDC, Cornforth reagent)
- Periodinane by Dess-Martin
- Oxalyl chloride with dimethylsulfoxide (DMSO) for Swern
- oxidation of secondary alcohols to ketones
(dichromate)
/pyridine (Collins reagent)- Chromium pyridinium compound (PCC)
- Dichromate of pyridinium (PDC, Cornforth reagent)
- Periodinane by Dess-Martin
- Oxalyl chloride and dimethyl sulfoxide (DMSO) (Swern oxidation)
/acetone (Jones oxidation)- Acetone with aluminum isopropoxide (Oppenauer oxidation)
To learn more about oxidation of alcohols with the given link
brainly.com/question/7207863
#SPJ4
<u>Question:</u>
Identify the reagents necessary to achieve each of the following transformations




Explanation:
According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.
As the given reaction is as follows.

(a) When increase the temperature of the reactants or system then equilibrium will shift in forward direction where there is less temperature. It is possible for an endothermic reaction.
Thus, formation of
will increase.
- (b) When we decrease the volume (at constant temperature) of given reaction mixture then it implies that there will be increase in pressure of the system. So, equilibrium will shift in a direction where there will be decrease in composition of gaseous phase. That is, in the backward direction reaction will shift.
Hence, formation of
will decrease with decrease in volume.
- When we increase the mount of
then equilibrium will shift in the direction of decrease in concentration that is, in the forward direction.
Thus, we can conclude that formation of
will increase then.
Answer:
First, place no. 5 in front of the CO2 in order to balance the carbon atoms. Next, place no. 6 in front of H2O to balance the hydrogen atoms. Lastly place no. 8 in front of the O2 so that there are 16 oxygen atoms on both sides of the reaction.