Answer:
The answer to the question is
The object would fall 57.625 m in the first 5 seconds
Explanation:
To solve the question, we note that
the height of fall = 490 ft = 149.352 m
Time to touch the ground = 7 seconds
We are required to find out how far the object falls in the first 5 seconds
We apply the relation
S = u·t + 0.5×g·t ² = We then have
149.352 = U×7+0.5*9.81*49 From where u = -13 m/s
Therefore to find how far it falls in the first 5 seconds, we have
-13*5 + 0.5*9.81*25 = 57.625 m
Answer:
The value is
Explanation:
From the question we are told that
The mass of the bullet is
The mass of the wood is
The height attained by the combined mass is
Generally according to the law of energy conservation
Here is the kinetic energy of the bullet before collision.
and is the potential energy of the combined mass of bullet and wood at the height h which is mathematically represented as
So
=>
The force the box is exerting on Manuel is the weight of the box, downward:
and this force is perfectly balanced by the constraint reaction applied by Manuel's hand, pushing upward.
Force = (mass) x (acceleration)
= (0.025 kg) x (5 m/s²)
= 0.125 Newton
Answer: F = 102141N
Explanation: <em><u>Newton's 2nd Law</u></em> states that a force can change the motion of a body. The relation is given by
F = m.a
whose units are:
[F] = N
[m] = kg
[a] = m/s²
Jenny's car, at the moment of the break, had acceleration:
a = 78.57 m/s²
Then, Force is
F = 1300*78.57
F = 102141 N
<u>Jenny's car experienced a force of </u><u>magnitude 102141N.</u>