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8_murik_8 [283]
3 years ago
6

How can people protect themselves from uranium? Need answer ASAP

Physics
1 answer:
umka21 [38]3 years ago
4 0
StandardsIn practice, radiation protection is based on the understanding that small increases over natural levels of exposure are not likely to be harmful but should be kept to a minimum. To put this into practice, the International Commission for Radiological Protection (ICRP) has established recommended standards of protection (both for members of the public and radiation workers) based on three basic principles:
Justification. No practice involving exposure to radiation should be adopted unless it produces a net benefit to those exposed or to society generally.
Optimisation. Radiation doses and risks should be kept as low as reasonably achievable (ALARA), economic and social factors being taken into account.
Limitation. The exposure of individuals should be subject to dose or risk limits above which the radiation risk would be deemed unacceptable.
These principles apply to the potential for accidental exposures as well as predictable normal exposures.Underlying these is the application of the 'linear hypothesis' based on the idea that any level of radiation dose, no matter how low, involves the possibility of risk to human health. This assumption enables 'risk factors' derived from studies of high radiation dose to populations (e.g. from Japanese atomic bomb survivors) to be used in determining the risk to an individual from low doses (ICRP Publication 60). However the weight of scientific evidence does not indicate any cancer risk or immediate effects at doses below about 50 millisieverts (mSv) per year.Based on these conservative principles, the ICRP recommends that the additional dose above natural background and excluding medical exposure should be limited to prescribed levels. These are: 1 mSv/yr for members of the public, and 20 mSv/yr averaged over five years for radiation workers, who are required to work under closely-monitored conditions.Early uranium mining, for example in Soviet-occupied East Germany between 1946 and 1953, had a poor safety record. Lack of appropriate protection exposed German miners to a variety of health hazards including high levels of radiation, toxic chemicals (such as arsenic), crystalline silica and dust. The mining operation, known as Wismut, took place on a very large scale, and occupational exposure is thought to be attributable to thousands of cases of lung cancer and other health impairments. It is estimated that in some East German mines, mean radiation exposures were 750 mSv/yr, well above the modern-day regulated limit of 20 mSv/yr.The modern uranium mining industry is regulated and has a good safety record. Radiation dose records compiled by major mining companies under the scrutiny of regulatory authorities have shown that company employees are not exposed to radiation doses in excess of defined limits during normal operations. The maximum dose received is normally about half of the 20 mSv/yr limit and the average is considerably less. Low-level radiation doses for employees are achieved through a variety of protective measures (see below).Aside from radiation, the occupational health and safety hazards of modern uranium mining are no greater than, nor distinct from, other comparable mining operations.
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Which refers to a material that causes a wave to bounce off of it?
ale4655 [162]

Answer:

the answer to the question is a reflector

7 0
2 years ago
A man pushes a 35.2 kg box across a frictionless floor with a force of 128 N. What is the acceleration of the box
vodka [1.7K]
The formula for Force is F = MA, or Force is equivalent to the product of Mass and Acceleration. 

F = 128N.
M = 35.2kg.

128 = 35.2A
Divide both sides by 35.2 to solve for the acceleration.
A = ~3.636

The acceleration is 3.636 m/s^2.

I hope this helps!
4 0
3 years ago
Read 2 more answers
An airplane starts from rest and accelerates at 10.8 m/s2 . what is its speed at the end of a 400 m long runway?
Cloud [144]

The final speed of an airplane is v = 92.95 m/s

The rate of change of position of an object in any direction is known as speed i.e. in other word, Speed is measured as the ratio of distance to the time in which the distance was covered.

Solution-

Here given,

Acceleration a= 10.8 m/s2 .

Displacement (s)= 400m

Then to find final speed of airplane v=?

Therefore from equation of motion can be written as,

v²=u²+ 2as

where, u is initial speed, v is final speed ,a is acceleration and s is displacement of the airplane. Therefore by putting the value of a & s in above equation and (u =0) i.e. the initial speed of airplane is zero.

v²= 2×10.8 m/s²×400m

v²=8640m/s

v=92.95m/s

hence the final speed of airplane v =92.95m/s

To know more about speed

brainly.com/question/13489483

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5 0
2 years ago
A man is dragging a trunk up the loading ramp of a mover’s truck. The ramp has a slope angle of 20.0°, and the man pulls upward
AleksandrR [38]

Answer:

(a)  104 N

(b) 52 N

Explanation:

Given Data

Angle of inclination of the ramp: 20°

F makes an angle of 30° with the ramp

The component of F parallel to the ramp is Fx = 90 N.  

The component of F perpendicular to the ramp is Fy.

(a)  

Let the +x-direction be up the incline and the +y-direction by the perpendicular to the surface of the incline.  

Resolve F into its x-component from Pythagorean theorem:  

Fx=Fcos30°

Solve for F:  

F= Fx/cos30°  

Substitute for Fx from given data:  

Fx=90 N/cos30°

   =104 N

(b) Resolve r into its y-component from Pythagorean theorem:

     Fy = Fsin 30°

   Substitute for F from part (a):

     Fy = (104 N) (sin 30°)  

          = 52 N  

5 0
3 years ago
What amount of heat is required to raise the temperature of 25 grams of copper to cause a 15ºC change? The specific heat of copp
Lina20 [59]

The amount of heat required is B) 150 J

Explanation:

The amount of heat energy required to increase the temperature of a substance is given by the equation:

Q=mC\Delta T

where:

m is the mass of the substance

C is the specific heat capacity of the substance

\Delta T is the change in temperature of the substance

For the sample of copper in this problem, we have:

m = 25 g (mass)

C = 0.39 J/gºC (specific heat capacity of copper)

\Delta T = 15^{\circ}C (change in temperature)

Substituting, we find:

Q=(25)(0.39)(15)=146 J

So, the closest answer is B) 150 J.

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

3 0
3 years ago
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