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pashok25 [27]
3 years ago
7

The mass of an object relates to __________

Physics
2 answers:
dusya [7]3 years ago
5 0
Hi Lsavagecurry

The mass of an object relates to weight. The definition of mass is weight, like how heavy something is, say for example I have a balance scale which is the picture below and I put a rock on one side and 4 more smaller rocks on the other side, of course its balanced, u might have thought one or the other is stronger but its equal because the 4 rocks were not as big as the one on the left, they were smaller but due to their quantity it equaled their same mass, but another ex is I put a elephant and a mouse on a scale, who has more mass, answer is elephant because it weighs way more than a mouse, and a mouse barely weighs anything, but its not because of mass only, if maybe there were a billion mouses against that elephant on a scale maybe they could balance it, quantity can also help as well. I hope this helps you with your question and I take no credit for the images below I got them from google.com

disa [49]3 years ago
5 0
It is either force,motion or energy:) hope I helped!<span />
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Nookie1986 [14]

Answer:

Force(Romeo moving) = 5,000 N

Explanation:

Given:

Mass of horse = 900 kg

Acceleration = 20 km/hr

Find:

Force(Romeo moving)

Computation:

Acceleration = 20 km/hr

Acceleration in m/s = 20 / 3.6 = 5.555556 m/s²

Force = m x a

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Force(Romeo moving) = 5,000 N

3 0
3 years ago
Which dog has the most kinetic energy
Blababa [14]
The formula to find the kinetic energy is:

Ek= 1/2 × m × v^2

1. Ek= 1/2×15×3^2
= 67.5 J

2.Ek= 1/2×8×4^2
=64 J

3.Ek= 1/2×12×5^2
= 150 J

4.Ek= 1/2×10×6^2
= 180 J

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4 0
3 years ago
A 5-cm-high peg is placed in front of a concave mirror with a radius of curvature of 20 cm.
Andrei [34K]

Answer:

Explanation:

Using the magnification formula.

Magnification = Image distance(v)/object distance(u) = Image Height(H1)/Object Height(H2)

M = v/u = H1/H2

v/u = H1/H2...1

3) Given the radius of curvature of the concave lens R = 20cm

Focal length F = R/2

f = 20/2

f = 10cm

Object distance u = 5cm

Object height H2= 5cm

To get the image distance v, we will use the mirror formula

1/f = 1/u+1/v

1/v = 1/10-1/5

1/v = (1-2)/10

1/v =-1/10

v = -10cm

Using the magnification formula

(10)/5 = H1/5

10 = H1

H1 = 10cm

Image height of the peg is 10cm

4) If u = 15cm

1/v = 1/f-1/u

1/v = 1/10-1/15

1/v = 3-2/30

1/v = 1/30

v = 30cm

30/15 = H1/5

15H1 = 150

H1/= 10cm

5) if u = 20cm

1/v = 1/f-1/u

1/v = 1/10-1/20

1/v = 2-1/20

1/v = 1/20

v = 20cm

20/20 = H1/5

20H1 = 100

H1 = 5cm

6) If u = 30cm

1/v = 1/f-1/u

1/v = 1/10-1/30

1/v = 3-1/30

1/v = 2/30

v = 30/2 cm

v =>15cm

15/30 = Hi/5

30H1 = 75

H1 = 75/30

H1 = 2.5cm

4 0
3 years ago
Scientific way of thinking
noname [10]

Answer:

huh,? can you explain the question more please

7 0
4 years ago
Read 2 more answers
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Lemur [1.5K]
Hope this helps you.

6 0
3 years ago
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