Explanation:
formula: <u>Mass</u>
Density x volume
2a) m=10kg v=0.3m³
10÷0.3=33.3 kg/m
2b) m = 160 kg V=0.1m³
160÷0.1=1600 kg/m
2c) m = 220 kg V = 0.02m³
220÷0.02=11000 kg/m
A wooden post has a volume of 0.025m³ and a mass of 20kg. Calculate its density in kg/m.
density = volume ÷ mass
20÷ 0.025=800 kg/m
Challenge: A rectangular concrete slab is 0.80m long, 0.60 m wide and 0.04m thick. Calculate its volume in m³.
Formula : Length x width x height = Volume
0.80 x 0.60 x 0.04 = 0.0192m³
B) The mass of the concrete slab is 180 kg. Calculate its density in kg/m.
density = volume ÷ mass
180 ÷ 0.0192 = 9375 kg/m
Answer:
real, inverted, and smaller than the object
Explanation:
When the object is placed beyond the center of curvature, the image will formed between the focus and the center of curvature. The size of the image is diminished and its nature is real and inverted.
The whole description is shown in the attached figure. It is clear that the size of the image is smaller than the object.
Answer:
it maybe correct
Explanation:
You can feel an increase of pressure on your eardrums. ... The deeper you go under the sea, the greater the pressure of the water pushing down on you
25g of mass will require 25g of opposite force on the ball from the road and opposition is moving upward to work on the ball
Answer:
The width of the central bright fringe is 7.24 mm.
Explanation:
Given that,
Wavelength = 632.8 nm
Width d= 0.350 mm
Distance between screen and slit D= 2.00 m
We need to calculate the distance
Using formula of distance
Put the value into the formula
We need to calculate the width of the central bright fringe
Using formula of width
Put the value into the formula
Hence, The width of the central bright fringe is 7.24 mm.
