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3 years ago

What is the voltage in a circuit that has a current of 10.0 amps and a resistance of 28.5 ohms?

2 answers:

5 0

<span>Ohm's law deals with the relation between voltage and current in an ideal conductor. It states that: Potential difference across a conductor is proportional to the current that pass through it. It is expressed as V=IR.

V = 10.0 A (28.5 ohms) = 285 V </span>

Stella [2.4K]3 years ago

3 0

V = I · R = (10 A) · (28.5 Ω) = 285 volts .

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Direction of resultant = 3.97°

Explanation:

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$R=\sqrt{R_x^2+R_y^2}\\\Rightarrow R=\sqrt{(\vec{u}_x+\vec{v}_x)^2+(\vec{u}_y+\vec{v}_y)^2}\\\Rightarrow R =\sqrt{(70cos40+85cos335)^2+(70sin40+85sin335)^2}\\\Rightarrow R =131.15$

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