Two hockey pucks, each with a mass of 0.2 kg, slide across the ice and
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The electric field produced by a large flat plate with uniform charge density on its surface can be found by using Gauss law, and it is equal to
where
is the charge density
is the vacuum permittivity
We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
where
We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
Answer:
- 2.32
- 0.43
Explanation:
12.0 kv primary voltage
315 kv secondary voltage ( converted voltage ) V1 or Vo
v2 (Vn)= 730 kv new secondary voltage
a) Ratio of turns in 730 kv to turns in 315 kv
=
therefore the ratio of turns = 2.317 ≈ 2.32
B) ratio of the new current output to the old current output for the same power input to the transformer
since the power input is the same
equation 1
Vp = primary voltage, Vo = old secondary voltage, Vn = new secondary voltage, In = new secondary current, Io = old secondary current
therefore equation 1 becomes
= 315 / 730 = 0.43