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Ratling [72]
3 years ago
9

How does heat transfer between objects

Chemistry
1 answer:
pentagon [3]3 years ago
8 0

Answer:

Explanation:

       Heat can transfer between objects in two different ways. Generally, heat will travel from places of higher heat to places of lower heat.

       The first is conduction. This is when the object being heated and releasing heat are in direct contact. Not as much heat is lost in this process, since the thermal energy has nowhere else to go except for the object it is touching. An example would be putting a kettle on a hot stove, but it could also be grabbing a cold pole with your relatively warm hands.

       The second is convection. This is where heat is radiated into the air, and thus, transferred by the air, to another object. The actual heat that you feel is actually electromagnetic waves, and its transfer from an object is called electromagnetic radiation. Convection is the heat you feel from a near fire or a space heater. This is also why wind is present in our atmosphere.

       There is also radiation. This is caused from the burning or breaking down of a substance. This might come from the sun.

I hope I did enough to deserve the 45 points!

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3 years ago
 How much energy is needed to raise the temperature of 125g of water from 25.0oC to 35.0oC?  The specific heat of water is 4.184
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To find the amount of energy need to raise the temperature of 125 grams of water from 25.0° C to 35.0° C, we will need to use the formula: q = mcΔt.

In this formula, q is the heat absorbed, m is the mass, c is the specific heat, and Δt is the change in temperature, which is found by final temperature minus the initial temperature.

Firstly, we can find the change in temperature. We are given the initial temperature, which is 25.0° C and the final temperature, which is 35.0° C. It is found by subtract the final temperature from the initial temperature.

35.0° C - 25.0° C = 10.0° C

We are also given the specific heat and the grams of water. With that, we can substitute the given values into the equation and multiply.

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q = 523 J/°C × 10.0° C

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Therefore, it will take 5230 joules (J) to raise the temperature of the water.

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