Answer: A.) Removing a few marbles from the petri dish and stirring the rest around as energy is added
B) The high temperature makes the gas molecules spread apart according to Charles's law because this law describes how a gas will behave at constant pressure.
Explanation: The phase transition from solid to liquid involves the use of energy to make the molecules present in solid to break the inter molecular forces and to start moving away from each other as in liquid. The molecules in solid are closely packed whereas in liquids they are loosely packed. Thus less number of molecules are present per unit volume in a liquid. Thus the marbles have to be removed to show less density and the energy has to supplied. Removing all but two marbles from the petri dish and shaking them vigorously as energy is added will give us a more disorderd state called gas in which the molecules are very far apart and the density is least.
B) According to Boyle's law the pressure is inversely proportional to the volume of the gas at constant temperature and constant number of moles.
(At constant temperature and number of moles)
According to Charle's law the volume is directly proportional to the temperature of the gas at constant pressure and constant number of moles.
(At constant pressure and number of moles)
Thus as temperature of the gas increases , the volume also increases, and the density decreases. the gas becomes lighter and thus rises up.
Hello!
To find the amount of energy need to raise the temperature of 125 grams of water from 25.0° C to 35.0° C, we will need to use the formula: q = mcΔt.
In this formula, q is the heat absorbed, m is the mass, c is the specific heat, and Δt is the change in temperature, which is found by final temperature minus the initial temperature.
Firstly, we can find the change in temperature. We are given the initial temperature, which is 25.0° C and the final temperature, which is 35.0° C. It is found by subtract the final temperature from the initial temperature.
35.0° C - 25.0° C = 10.0° C
We are also given the specific heat and the grams of water. With that, we can substitute the given values into the equation and multiply.
q = 125 g × 4.184 J/g °C × 10.0° C
q = 523 J/°C × 10.0° C
q = 5230 J
Therefore, it will take 5230 joules (J) to raise the temperature of the water.
Since there are no given items, I will give a general answer. Energy....or the lack of it. Examples: Heat, electricity, force (when an item is moving and it impacts something, it heats up...friction is an example of this), etc