The component of the weight of the box along the surface is 34.9N.
<u>Explanation:</u>
Given that
Mass of the box m=21kg
Angle of inclination θ=10°
Acceleration due to gravity g=9.8 
Weight of an object is the force with which the earth attracts the object. Since weight is a force its unit is Newton(N). When an object is placed on a surface that has no inclination, its weight is given by the expression
W=mg
where m denotes mass of the object and g denotes the acceleration due to gravity.
When the surface has an inclination, the weight of the object can be resolved into two components that are parallel and perpendicular to the surface.
The component of weight parallel to the surface is given by
W=mgsinθ
where θ is the angle of inclination
The component of weight perpendicular to the surface is given by
W=mgcosθ
In the given problem, we have to find out the parallel component of weight
W=mgsinθ

The component of the weight of the box along the surface is 34.9N
Answer:
Between a 12 gauge and a 22 gauge wire: the 12 gauge wire
Explanation:
Since the resistance in a wire is given by:

If both wires are made out of copper, the resistivity
is the same.
The difference will remain in the cross area. The one with less area is the one with the greatest resistance.
Between the 2 gauge wires (22 and 12), the 12 gauge wire, with a diameter of 2.05mm is the one with smallest resistance.
Answer:
let us use the expression v = ./2gS in both the cases.
a) In the first case g = 9.8 m/s^2 and S = 10.3 m.
So v = 14.21 m/s
b) in the second case, g = 1.64 m/s^2 and S = 4.2 m = 3.71 m/s
00
Explanation:
<span>The current system of units has three standard units: The meter, kilogram, and second. These three units form the mks-system or the metric system. A meter is a unit of length, currently defined as the distance light travels within 1/299782458th of a second. A kilogram is a unit of mass.</span>