Answer:
B) Observations and experimentation
Explanation:
this is the most suitable words to describe how is Science used in describing the world. we collect the knowledge in organized way and provide it with explanations and start to predict about the future world
ِAny Inventions are based on Science and no Inventions without Observations and experimentation
No one of us have went to a chemistry or a physics labs without using Observations and experimentation
Answer:
See explanation.
Explanation:
Hello,
In this case, we could have two possible solutions:
A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:
![M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol](https://tex.z-dn.net/?f=M_%7BCuSO_4%7D%3Dm_%7BCu%7D%2Bm_%7BS%7D%2B4%2Am_%7BO%7D%3D63.546%20g%2Fmol%2B32.00g%2Fmol%2B4%2A16.00g%2Fmol%5C%5C%5C%5CM_%7BCuSO_4%7D%3D159.546g%2Fmol)
That is the mass of copper (II) sulfate contained in 1 mol of substance.
B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:
![M=\frac{n_{solute}}{V_{solution}}](https://tex.z-dn.net/?f=M%3D%5Cfrac%7Bn_%7Bsolute%7D%7D%7BV_%7Bsolution%7D%7D)
So you can solve for the moles of the solute:
![n_{solute}=M*V_{solution}](https://tex.z-dn.net/?f=n_%7Bsolute%7D%3DM%2AV_%7Bsolution%7D)
Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:
![n_{solute}=1mol/L*1.5L=1.5mol](https://tex.z-dn.net/?f=n_%7Bsolute%7D%3D1mol%2FL%2A1.5L%3D1.5mol)
But this is just a supposition.
Regards.
The receive very little rainfall