Which factor would slow down a chemical reaction? (Choose all that apply)
1 answer:
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Answer:
-5,921x10⁶J/mol
Explanation:
Internal energy change (ΔU) for the reaction of combustion in the bomb calorimeter is:
ΔU = q calorimeter + q solution
Where:
q calorimeter is Ccal×ΔT (Ccal=4042J/°C) and (ΔT is 29,30°C-22,64°C=<em>6,66°C</em>)
q solution is c×m×ΔT (c= 4.184 J/g°C), (m=1502g H₂O), (ΔT is 29,30°C-22,64°C=<em>6,66°C</em>)
Replacing:
ΔU = 26920J + 41854J = <em>68774 J</em>
This energy is per g of n-hexane, now, per mole of n-hexane:
= -<em>5,921x10⁶J/mol</em>
<em>-negative because the energy is produced-</em>
I hope it helps!