How much heat will be produced when 0.58 moles of

A potassium isotope has a half-life of 1.25 billion years. Given that scientists estimate Earth's age to be 4.6 billion years, w

dmitriy555 [2]

Answer:

More than 75%

Explanation:

2.5billion -> 1.25Billion

8 0

3 years ago

An atom with a positive or negative change is call

Evgen [1.6K]

Answer:

An atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom. When an atom is attracted to another atom because it has an unequal number of electrons and protons, the atom is called an ION.

3 0

4 years ago

Read 2 more answers

Rank these ions according to ionic radius. Rb+ Sr2+ As3- Se2- Br-

Bond [772]

Atomic radius increases going down and decreases left to right. Look at where these are located on the periodic table and apply this.

6 0

4 years ago

A train travels 803.98 meters in 1 minute what is the trains average rate of speed

TEA [102]

Answer:

Approximately 13.4 meters per second (m/s)

Explanation:

We can divide the distance by 60 seconds to find the trains average rate of speed.

803.98 / 60 ≈ 13.4

Best of Luck!

7 0

3 years ago

A voltaic cell made of a Cr electrode in a solution of 1.0 M in Cr3+ and a gold electrode in a solution that is 1.0 M in Au3+.

Vikki [24]

Answer: a) Anode: $Cr\rightarrow Cr^{3+}+3e^-$

Cathode: $Au{3+}+3e^-\rightarrow Au$

b) Anode : Cr

Cathode : Au

c) $Au^{3+}+Cr\rightarrow Au+Cr^{3+}$

d) $E_{cell}=2.14V$

Explanation: -

a) The element Cr with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element Au with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.

At cathode: $Au{3+}+3e^-\rightarrow Au$

At anode: $Cr\rightarrow Cr^{3+}+3e^-$

b) At cathode which is a positive terminal, reduction occurs which is gain of electrons.

At anode which is a negative terminal, oxidation occurs which is loss of electrons.

Gold acts as cathode ad Chromium acts as anode.

c) Overall balanced equation:

At cathode: $Au{3+}+3e^-\rightarrow Au$ (1)

At anode: $Cr\rightarrow Cr^{3+}+3e^-$ (2)

Adding (1) and (2)

$Au^{3+}+Cr\rightarrow Au+Cr^{3+}$

d) $E^0_(Cr^{3+}/Cr)$ = -0.74 V