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Tom [10]
3 years ago
9

100 POINTS BRAINLIEST PLEASE ANSWER NOW I NEED THE ANSWER

Physics
1 answer:
steposvetlana [31]3 years ago
6 0

This shows the sunlight shining on the moon is creating a shadow. The part of the shadow that we don’t see from Earth is called the eclipse. Since the Earth gets a shadow from the moon, that causes the rest of the Earth to light up which causes a lunar eclipse.

Explanation:

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Which condition must be met in order for an equation to be balanced?
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Answer:

There must be an equal amount of each element on both sides of the equation. Hope this helps and please marks as the brainliest.

Explanation:

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3 years ago
A thundercloud has an electric charge of 48.8 C near the top of the cloud and –41.7 C near the bottom of the cloud. The magnitud
IceJOKER [234]

Answer: 1.51 km

Explanation:

<u>Coulomb's Law:</u> The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.

Or,   \vec{F}=k \frac{Q_{1} Q_{2}}{r^{2}}

Where Q1 and Q2 are magnitude of two charges and r is distance between them:

<u>Given:</u>

Q1 = Charge near top of cloud = 48.8 C

Q2 = Charge near the bottom of cloud = -41.7 C

Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N

k = 8.99 x 109Nm^2/C^2

<u>So,</u>

\begin{aligned}&7.98 \times 10^{6}=\left(8.99 \times 10^{9} \mathrm{Nm}^{2} / \mathrm{C}^{2}\right) \frac{48.8 \mathrm{C} \times 41.7 \mathrm{C}}{\mathrm{r}^{2}} \\&r=\sqrt{\frac{1.8294 \times 10^{13}}{7.98 \times 10^{6}}}=1.514  \times 10^{3} \mathrm{~m}=1.51 \mathrm{~km}\end{aligned}

Therefore, the separation between the two charges (r) = 1.51 km

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2 years ago
When we study the earth and its people, we are studying ___________________. a) desalination b) geography c) irrigation d) absol
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Geography Earth studying
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A 10 Kg ball is rolling at 2.5 m/s. It is then hit from behind with a bat that puts a 300 N force on the ball for a quick .3 sec
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Answer: g. gg g rfrcdv

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vfv g bygyb

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The velocity of a wave with a wavelength of 4.700 m and frequency of 54.00 Hz is
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The answer is 253.8 m/s
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