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laila [671]
3 years ago
7

Are photosynthesis and cellular respiration part of the land-based carbon cycle of water-based carbon cycle

Chemistry
1 answer:
Dmitrij [34]3 years ago
3 0
It would be the water based carbon cycle
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What is the application of Complexometric titration? ​
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Explanation:

Complexometric titration (sometimes chelatometry) is a form of volumetric analysis in which the formation of a colored complex is used to indicate the end point of a titration. Complexometric titrations are particularly useful for the determination of a mixture of different metal ions in solution.

hope it will help u ✌️

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How many moles of CO2 are produced
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Answer:

30.0 mol CO₂

Explanation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

To answer this problem we need to convert moles of C₃H₈ into moles of CO₂: We'll do that by using the <u>stoichiometric coefficients</u>, using a conversion factor that has C₃H₈ moles in the denominator and CO₂ moles in the numerator:

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Why is the<br> chemical formula for sodium<br> chloride NaCl, and not NaCI6<br> or Na6CI
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3 years ago
Students in Mr. Brant's class designed an experiment to test which baseball bat will hit the ball the longest distance? In this
Mama L [17]
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Suppose that 6.2 mL of 2.1 M KOH(aq) is transferred to a 250 mL volumetric flask and diluted to the mark. It was found that 36.9
galina1969 [7]

Answer:

0.928 M

Explanation:

The concentration of acid can be determined by using the volume used and the concentration and volume used of base.

We will use the law of equivalence of moles.

M₁V₁=M₂V₂

M₁ = concentration of base used

V₁ = volume of base used

M₂ = concentration of acid used =? (to be determined)

V₂ = volume of acid used

The initial concentration of KOH used is diluted so let us find the final concentration of KOH after dilution

initial moles = final moles

initial concentration X initial volume = final concentration X final volume

6.2 X 2.1 = 250 X final concentration

final concentration = 0.052 M = M₁

V₁ = 36.9 mL

V₂ = 6.2 mL

Here with each mole of phosphoric acid three moles of KOH are used.

Therefore

3 M₁V₁ = M₂V₂

M₂ = \frac{V_{2}}{3M_{1}V_{1}}=0.928M

3 0
4 years ago
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