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Anika [276]
3 years ago
6

2 Calculate the mass of a car that hits a wall, during an accident, with a force of 961 N and an acceleration of 31m/s2. (4D) (F

= m * a) *
Physics
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer: 31kg

Explanation:

(F=mxa)

Rearranged

M=f÷a

961÷31=31

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In an experiment designed to measure the Earth's magnetic field using the Hall effect, a copper bar 0.550 cm thick is positioned
motikmotik

Answer:

B= 4.197*10^-5T

Explanation:

We know that the magnetic Field of the Earth is 50\mu T, so the equation for

Hall effect voltage und magnetic field are defined as,

\Delta V_H = \frac{IB}{nqt}

B=\frac{nqt\Delta V_h}{I}

So,

B=\frac{(8.48*10^{28})(1.6*10^{-19})(0.0055)(4.5*10^-{12})}{8}

B= 0.00004197

B= 4.197*10^{-5}T

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Need help identifying the rest of the elements!
gregori [183]
I think that number five is lithium
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3 years ago
an athlete in a hammer-throw event swings a 7.0-kilogram hammer in a horizontal circle at a constant speed of 12 meters per seco
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Answer:

ac = 72 m/s²

Fc = 504 N

Explanation:

We can find the centripetal acceleration of the hammer by using the following formula:

a_c = \frac{v^2}{r}

where,

ac = centripetal acceleration = ?

v = constant speed = 12 m/s

r = radius = 2 m

Therefore,

a_c = \frac{(12\ m/s)^2}{2\ m}

<u>ac = 72 m/s²</u>

<u></u>

Now, the centripetal force applied by the athlete on the hammer will be:

F_c = ma_c\\F_c = (7\ kg)(72\ m/s^2)

<u>Fc = 504 N</u>

6 0
3 years ago
The first person to map the Milky Way Galaxy using radio waves was
Art [367]

Answer:B

Explanation:Grote reber was the first scientist to map the milky way galaxy using radio waves.

7 0
3 years ago
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For a long ideal solenoid having a circular cross-section, the magnetic field strength within the solenoid is given by the equat
andrezito [222]

Answer:

Radius of the solenoid is 0.93 meters.

Explanation:

It is given that,

The magnetic field strength within the solenoid is given by the equation,

B(t)=5t\ T, t is time in seconds

\dfrac{dB}{dt}=5\ T

The induced electric field outside the solenoid is 1.1 V/m at a distance of 2.0 m from the axis of the solenoid, x = 2 m

The electric field due to changing magnetic field is given by :

E(2\pi x)=\dfrac{d\phi}{dt}

x is the distance from the axis of the solenoid

E(2\pi x)=\pi r^2\dfrac{dB}{dt}, r is the radius of the solenoid

r^2=\dfrac{2xE}{(dE/dt)}

r^2=\dfrac{2\times 2\times 1.1}{(5)}

r = 0.93 meters

So, the radius of the solenoid is 0.93 meters. Hence, this is the required solution.

4 0
4 years ago
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