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Verizon [17]
3 years ago
9

A tow truck exerts a force of 1850 N on a 840 kg car. What is the acceleration of the car during this time?

Physics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

<h2>2.2 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{1850}{840}  =  \frac{185}{84} \\   = 2.20238095...

We have the final answer as

<h3>2.2 m/s²</h3>

Hope this helps you

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Answer:

3.7 m/s^2

Explanation:

The period of a simple pendulum is given by:

T=2 \pi \sqrt{\frac{L}{g}}

where L is the length of the pendulum and g is the free-fall acceleration on the planet.

Calling L the length of the pendulum, we know that:

T_e = 2 \pi \sqrt{\frac{L}{g_e}}=1.50 s is the period of the pendulum on Earth, and g_e = 9.8 m/s^2 is the free-fall acceleration on Earth

T_m = 2 \pi \sqrt{\frac{L}{g_m}}=2.45 s is the period of the pendulum on Mars, and g_m = ? is the free-fall acceleration on Mars

Dividing the two expressions we get

\frac{T_e}{T_m}=\sqrt{\frac{g_m}{g_e}}

And re-arranging it we can find the value of the free-fall acceleration on Mars:

g_m = g_e \frac{T_e^2}{T_m^2}=(9.8 m/s^2)\frac{(1.50 s)^2}{(2.45 s)^2}=3.7 m/s^2

4 0
3 years ago
A heavy boy and a lightweight girl are balanced on a massless seesaw. If they both
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Answer:

D. Nothing will happen; the seesaw will still be balanced.

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D. Nothing will happen; the seesaw will still be balanced. Since both toruqes or momentums respect to the center have changed in the same amount (one-half their original distance) the seesaw will remain balanced, if the children change distance in a different amount then it will be out of balance

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The output force is

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