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Verizon [17]
3 years ago
9

A tow truck exerts a force of 1850 N on a 840 kg car. What is the acceleration of the car during this time?

Physics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

<h2>2.2 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{1850}{840}  =  \frac{185}{84} \\   = 2.20238095...

We have the final answer as

<h3>2.2 m/s²</h3>

Hope this helps you

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An inventor develops a stationary cycling device by which an individual, while pedaling, can convert all of the energy expended
mr Goodwill [35]

Answer:

Q=94185\ J

Explanation:

Given:

  • mass of water, m=0.3\ kg
  • initial temperature of water, T_i=20^{\circ}C
  • final temperature of water, T_f=95^{\circ}C
  • specific heat of water, c=4186\ J.kg^{-1}.K^{-1}

<u>Now the amount of heat energy required:</u>

Q=m.c.\Delta T

Q=0.3\times 4186\times (95-20)

Q=94185\ J

Since all of the mechanical energy is being converted into heat, therefore the same amount of mechanical energy is required.

4 0
3 years ago
An electric field of intensity 3.80 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.
lakkis [162]

Answer: 1.55 x 10⁴ Nm²c^-1

Explanation: The electric flux, electric field intensity and area are related by the formulae below.

Φ= EAcosθ,

Where Φ= electric flux (Nm²c^-1)

E =electric field intensity (N/m²)

A = Area (m²)

θ= this is angle between the planar area and the magnetic flux

For our question E=3.80KN/c= 3800 N/c

A= 0.700 x 0.350= 0.245m²

θ= 0° ( this is because the electric field was applied along the x axis, thus the electric flux will be parallel to the area).

Hence Φ= 3800 x 0.245 x cos(0)

= 3800 x 0.245 x 1 (value of cos 0° =1)

= 1.55 x 10⁴ Nm²c^-1

Thus the electric field is 1.55 x 10⁴ Nm²c^-1

4 0
3 years ago
A man has a mass of 85kg, what is his weight
Ostrovityanka [42]
The answer is he weighs 187.39 LBS/Pounds
5 0
3 years ago
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The electric current leaves the battery through the --- complete this blank
aev [14]
The bulb

Hope this helps!
5 0
3 years ago
How many ohms of resistance must be present in a circuit that has 240 volts and a current of 15 amps?
PIT_PIT [208]

Answer:

16 ohms

Explanation:

V= I ⋅ R

where,  V  is the net potential difference in the circuit,  I  is the current in the circuit and  R  is the net resistance of the circuit.  

In this case,  V = 240  volts,  I = 15  amperes.

240 = 15 ⋅ R  

⇒ R = 240/ 15 = 16  ohms

5 0
3 years ago
Read 2 more answers
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