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4 years ago

Can the ph scale be utilized for all acids (Arrhenius, Bronsted-Lowery, and Lewis)? Explain reasoning.

Chemistry

1 answer:

patriot [66]4 years ago

3 0

Answer:

No, the pH scale can not be utilized for all types of acids known

Explanation:

The pH scale is a scale that shows the degree of acidity or alkalinity of a substance. The pH scale is graduated from 0-14. The pH scale is mostly applied to Arrhenius acids. Recall that in the Arrhenius definition, an acid produces hydrogen ion in solution while a base produces hydroxide ion in solution. Hence we could easily measure or calculate the pH and pOH of Arrhenius acids. Arrhenius acids apply mostly to acid-base discussion in Aqueous media.

Beyond aqueous media, we can still apply the Brownstead-Lowry and Lewis definitions for acid and base. Some of these substances to which we apply these other definitions of acid and base do not necessarily contain hydrogen or hydroxide ions hence the pH scale can not be utilized in discussing their acid-base properties, hence the answer.

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The reaction a(g)⇌b(g) has an equilibrium constant of 5.8 and under certain conditions has q = 336. part a what can you conclude

Vika [28.1K]

Answer:

The answer is "As $Q=336$ , at high-temperature $\Delta G_{rxn}>0$ and When $K>1,$ $\Delta G^{\circ}_{rxn}>0$ ."

Explanation:

The equation for the reaction is:

$A(g) \leftrightharpoons B(g)$

$K=5.8\\\\Q=336$

At equilibrium,

$\Delta G^{\circ}_{rxn}>0$ $=-RT \ln \ K$

When k=5.8(>1), the value of $\ln k$ would be positive

So, $\Delta G^{\circ}_{rxn}$ is negative (< 0)

So if K > l, $\Delta G^{\circ}_{rxn}$

If the reaction is not in equilibrium so the equation is :

$\Delta G_{rxn}>0$ = $\Delta G^{\circ}_{rxn}$ $+RT \ln Q$

Substituting the expression:

$\Delta G_{rxn}>0$ $= (-RT \ln K) + RT \ln Q$

$= RT(\ln Q- \ln K)\\= RT(\ln (336)-\ln (5.8))\\= RT(4.06)$

It is the positive value for all temperatures.

So, As Q = 336, at the high temperature $\Delta G_{rxn}>0$ .

5 0

3 years ago

Correct name for #10 please

ira [324]

Answer:

CH₃CH(CH₃)CH(C₃H₇)CH₂CH(CH₃)₂:

4-isopropyl-2-methylpentane.

Explanation:

Step One: Draw the structure formula of this compound. Parentheses in the formula indicate substitute groups that are connected to the carbon atom to the left.

For example, the first (CH₃) indicates that the second carbon atom from the left is connected to:

the CH₃- on the left-hand side,
the -CH(C₃H₇)CH₂CH(CH₃)₂ on the right-hand side,
a hydrogen atom, and
an additional CH₃- group that replaced one hydrogen atom.

Each carbon atom in this compound is connected to four other atoms. All bonds between carbon atoms are single bonds.

The C₃H₇ in the second pair of parentheses is the condensed form of CH₃CH₂CH₂-. See the first sketch attached. Groups in parentheses are highlighted.

Step Two: Find the carbon backbone. The backbone of a hydrocarbon is the longest chain of carbon atoms that runs through the compound. See the second sketch attached. The backbone of this compound consists of seven carbon atoms and is highlighted in green. The name for this backbone shall be heptane.

Step Three: Identify and name the substitute groups.

The two substitute groups are circled in blue in the second sketch.

The one on the right -CH₃ is a methyl group.
The one on the left is branched. $\begin{aligned}\text{CH}_3-&\text{CH}-\text{CH}_3\\[-0.5em]&\;|\end{aligned}$ This group can be formed by removing one hydrogen from the central carbon atom in propane. The name for this group is isopropyl.

Step Four: Number the atoms.

Isopropyl shall be placed before methyl. Start from the right end to minimize the index number on all substitute groups. The methyl group is on carbon number two and the isopropyl group on carbon number four. Hence the name:

4-isopropyl-2-methylheptane.

5 0

4 years ago

Which of these elements has an atom with the most stable outer electron configuration? * Cl Ca Ne Na

SashulF [63]

Answer:

Neon (Ne) has the most stable outer electron configuration because the outer electron is completely filled and it has octet structure

Explanation:

The configuration of these elements is as follows;

Cl₁₇ = 2, 8,7 (the outer electron is 7)

Ca₂₀ = 2,8,8,2 (the outer electron is 2)

Ne₁₀ = 2,8 (the outer electron is 8)

Na₁₁ = 2,8,1 (the outer electron is 1)

Based on the outer electron value above, Neon (Ne) has the most stable outer electron configuration because the outer electron is completely filled and it has octet structure.

6 0

3 years ago

A chemistry student needs 15.0 g of methanol for an experiment. She has available 320. g of 44.4% w/w solution of methanol in wa

Makovka662 [10]

Answer:

33.8 g Solution

Explanation:

A chemistry student needs 15.0 g of methanol for an experiment. The concentration of ethanol in the solution is 44.4% w/w, that is, there are 44.4 g of methanol every 100 g of solution. The mass of solution that would contain 15.0 g of methanol is:

15.0 g Methanol × 100 g Solution/44.4 g Methanol = 33.8 g Solution

Since 33.8 g are required and 320. g are available, there is enough solution for the requirements.

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3 years ago

How many grams of CO2 are in 1.5L of a 1.2 M solution?

attashe74 [19]

The answer is d

whekdneluwjsbzhiwkshdiejhdjebeje

7 0

3 years ago