Answer:
Questions involving accelerating objects, including those in free fall, can be solved using three equations
y = 1/2at2 + v0t + y0
v = v0 + at
vf2 = v02 + 2 a (y - y0)
In this case, only the first equation is needed.
Since the object is falling the final height is 0 meters, the initial height is 370 m, and the acceleration is -9.8ms-2
Since the object is dropped, the initial velocity is 0.
0 = 1/2(-9.8)t2 + 370. t = sqrt(370/4.9) = 8.69 s
Explanation:
Answer:
mechanical energyis the sum of all potential and kinetic energy.hope it helps!
Answer:
The objects must be different temperatures.
Explanation:The objects must be different temperatures. eat will flow from Object 1 to Object 2 in examples 1, 2, and 4, and heat will flow from Object 2 to Object 1 in Example 3. Which factors affect heat transfer between a warm and a cool substance?
Answer:
Explanation:
Newton's law of universal gravitation states that the force experimented by a satellite of mass m orbiting Mars, which has mass 
at a distance r will be:
where 
is the gravitational constant.
This force is the centripetal force the satellite experiments, so we can write:
Putting all together:
which means:
![r=\sqrt[3]{\frac{GM}{4\pi^2}T^2}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7BGM%7D%7B4%5Cpi%5E2%7DT%5E2%7D)
Which for our values is:
![r=\sqrt[3]{\frac{(6.67\times10^{-11}Nm^2/kg^2)(6.39\times10^{23} kg)}{4\pi^2}(1.026\times24\times60\times60s)^2}=20395282m=20395.3km](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B%286.67%5Ctimes10%5E%7B-11%7DNm%5E2%2Fkg%5E2%29%286.39%5Ctimes10%5E%7B23%7D%20kg%29%7D%7B4%5Cpi%5E2%7D%281.026%5Ctimes24%5Ctimes60%5Ctimes60s%29%5E2%7D%3D20395282m%3D20395.3km)
Since this distance is measured from the center of Mars, to have the height above the Martian surface we need to substract the radius of Mars R=3389.5 km
, which leaves us with:
Answer:
Object appears to move forward at 1 cm/sec, then the velocity drops to zero for 3 sec and then moves forward at 2 cm/sec (11 - 3) / (10 - 6) = 2 cm/sec
