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kolezko [41]
3 years ago
5

Brainliest for whoever gets this right!

Physics
1 answer:
Llana [10]3 years ago
4 0

Answer: Find the answer in the explanation.

Explanation:

The earth wire act as a protective conductor in which hazardous current flows to the earth. Whenever there is a faulty flow of current, the earth wire will protect an iPad with a metal casing from eddy current by allowing the faulty current to flow directly to the earth.

With the use of fuse, an iPad with a metal casing will be protected from extreme heat due to overheating or electrical overloading as a result of short circuit.

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For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg
jeyben [28]

Answer:

<h2>Magnetic field strength in that region is 1.2 T</h2>

Explanation:

As we know by the formula of radius of charge moving in external field is given as

R = \frac{mv}{qB}

so we will have

R = 25 cm

m = 1.6 \times 10^{-27} kg

q = 1.6 \times 10^{-19} C

v = 0.10 \times 3 \times 10^8 m/s

now we have

0.25 = \frac{(1.6 \times 10^{-27})(3\times 10^7)}{(1.6 \times 10^{-19})B}

now we have

B = 1.2 T

8 0
3 years ago
An old iron beam was coated with an unknown metal. there is a crack on the coating and it is observed that the iron is rusting a
IgorLugansk [536]
Based on the given description above about the metal that is being used for fractures, the old metal coating that was used before was made of TIN, and now, the metal that is used to repair fractures in order to avoid further corrosion is ALUMINUM. Hope this answer helps.
3 0
4 years ago
A particle is attached to a spring and is pushed so that the spring is compressed more and more. As a result, the spring exerts
ad-work [718]
In order for particles to perform a simple harmonic motion, we must follow the law of force of the form F = -kx, where x is the displacement of the object from the equilibrium position and k is the spring constant. The force shown in <span>F = -kx is always the restoring force in the sense that the particles are pulled towards the equilibrium position.

The repulsive force felt when the charge q1 is pushed into another charge q2 of the same polarity is given by Coulomb's law
                                F = </span><span>k *q1* q2 / r^2.
</span>It is clear that Coulomb's law is an inverse-square relationship. It does not have the same mathematical form as the equation <span><span>F = -kx.</span> Thus, charged particles pushed towards another fixed charged particle of the same fixed polarity do not show a simple harmonic motion when released. Coulomb's law does not describe restoring force. When q1 is released, it just fly away from q2 and never returns.</span>
5 0
4 years ago
A packing crate slides down an inclined ramp at constant velocity. Thus we can deduce thatA) a frictional force is acting on itb
torisob [31]

Answer:

A) a frictional force is acting on it

Explanation:

The crate is sliding down the inclined ramp at constant velocity: constant velocity means zero acceleration, a = 0. According to Newton's second law:

F = ma

this also means that the net force acting along the direction of the slope is zero.

Without frictional force, there would be only one force acting along this direction: the component of the weight of the crane parallel to the slope, acting downward:

W_p = mg sin \theta

where \theta is the angle of the incline. Therefore, the net force along this direction would not be zero. In order to have a net force of zero, there must be another force acting upward on the crate: and the only force that is possibly acting on the crate against its direction of motion is the frictional force, whose magnitude must be equal to W_p, in order to produce a net force of zero (and therefore, a zero acceleration).

8 0
4 years ago
The quantity x to be determined from the equation X=P-Q.
Softa [21]

Answer:

the correct answer will be 6.82 %that is 7%

p(1.27)-q(0.83) =x=0.44

0.02+0.01 =0.03 (maximum uncertainty)

percentage uncertainty =0.03/0.44×100 %

=6.82%

=7%

Explanation: it was d on my end

5 0
2 years ago
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