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liq [111]
3 years ago
14

Kyle has a mass of 54 kg and is jogging at a velocity of 3 m/s. What is Kyle’s kinetic energy?

Physics
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer:243joules

Explanation:

Mass(m)=54kg

Velocity(v)=3m/s

Kinetic energy =(m x v^2)/2

Kinetic energy =(54 x 3^2)/2

Kinetic energy =(54 x 9)/2

Kinetic energy =486/2

Kinetic energy =243joules

Nady [450]3 years ago
5 0

Answer:

D

Explanation:

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Why are temperatures of the currents generally colder at the poles than the equator?
patriot [66]

Answer:

the answer is A

Explanation:

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3 years ago
Which of the following epidermal cells are the sensory receptors for touch?
never [62]
Merkel cells are the sensory receptors for touch. 
7 0
3 years ago
A parallel plate capacitor with air between the plates has a potential difference of 71.0 V. Determine the potential difference
Gwar [14]

Answer:

15.8 V

Explanation:

The relationship between capacitance and potential difference across a capacitor is:

q=CV

where

q is the charge stored on the capacitor

C is the capacitance

V is the potential difference

Here we call C and V the initial capacitance and potential difference across the capacitor, so that the initial charge stored is q.

Later, a dielectric material is inserted between the two plates, so the capacitance changes according to

C'=kC

where k is the dielectric constant of the material. As a result, the potential difference will change (V'). Since the charge stored by the capacitor remains constant,

q=C'V'

So we can combine the two equations:

CV=CV'\\CV=(kC)V'\\V'=\frac{V}{k}

and since we have

V = 71.0 V

k = 4.50

We find the new potential difference:

V'=\frac{71.0}{4.50}=15.8 V

6 0
3 years ago
The distance recorded for riding a motorcycle on its rear wheel without stopping is more than 320 km! Suppose the rider in this
antiseptic1488 [7]

Answer:

<h3>14.97m/s</h3>

Explanation:

Given

Initial velocity of the car u = 8m/s

Distance travelled by the rider S = 40m

Acceleration a = 2m/s²

Required

rider's velocity after the acceleration v

Using the equation of motion

v² = u²+2as

v² = 8²+2(2)(40)

v² = 64+160

v² = 224

v = √224

v = 14.97m/s

Hence the rider's velocity after the acceleration is 14.97m/s

5 0
3 years ago
Please anyone post any class 9 physics question​
aalyn [17]

Answer:

I will but can you just wait for some minutes cus I am in a hurry now.

sorry that pic is a little blurry

6 0
2 years ago
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