In a reversible reaction, both forward and reverse directions of the reaction generally occur at the same time. While reactants are reacting to produce products, products are reacting to produce reactants. Often, a point is reached at which forward and reverse directions of the reaction occur at the same rate.
To solve this process it is necessary to consider the concepts related to the relations between pressure and temperature in an adiabatic process.
By definition the relationship between pressure and temperature is given by

Here
P = Pressure
T = Temperature
The ratio of specific heats. For air normally is 1.4.
Our values are given as,

Therefore replacing we have,


Solving for 


Therefore the maximum theoretical pressure at the exit is 
Answer:
- translation
- rotation, traslation
- traslation, rotation
- vibrating
Explanation:
El movimiento de un cuerpo cae por su propio peso <u>traslación</u>.
El movimiento de las ruedas de una bicicleta al ser pedaleada <u>rotación, traslación</u>.
El movimiento de la Tierra alrededor de sol <u>traslación, rotación</u>.
El movimiento de la cuerda de una guitarra cuando se está tocando música <u>vibración</u>.
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The movement of a body falls under its own weight <u>translation</u>.
The movement of the wheels of a bicycle when being pedaled <u>rotation, translation.</u>
The movement of the Earth around the sun, <u>translation, rotation</u>.
The movement of a guitar string when playing music <u>vibrating</u>.
If Earth were 10.0 times farther away from the Sun than it is now, 100 times weaker would the gravitational force between the Sun and Earth.
What is Gravitational Force?
According to Newton's universal law of gravitation, The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them.
What causes gravitational force?
Earth's gravity comes from all its mass. All its mass makes a combined gravitational pull on all the mass in your body. That's what gives you weight. And if you were on a planet with less mass than Earth, you would weigh less than you do here.
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The tension on the wire is 52.02 N.
From the question, we have
Density of aluminum = 2700 kg/m3
Area,
A = πd²/4
A = π x (4.6 x 10⁻³)²/4
A = 1.66 x 10⁻⁵ m²
μ = Mass per unit length of the wire
μ = ρA
μ = 2700 kg/m³ x 1.66 x 10⁻⁵ m²
μ = 0.045 kg/m
Tension on the wire = √T/μ
34 = √T/0.045
34² = T/0.045
T = 52.02 N
The tension on the wire is 52.02 N.
Complete question:
The density of aluminum is 2700 kg/m3. If transverse waves propagate at 34 m/s in a 4.6-mm diameter aluminum wire, what is the tension on the wire.
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