Is oxygen and fluorine in the same family

You are at school 7:15-1:45(6.5) every day. how many second is this

Airida [17]

23400 is the answer i calculated

5 0

3 years ago

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som

jek_recluse [69]

The question is incomplete, the complete question is:

A certain substance X has a normal freezing point of $-6.4^oC$ and a molal freezing point depression constant $K_f=3.96^oC.kg/mol$ . A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at $-13.6^oC$ . Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.

<u>Answer:</u> The mass of glycine that can be dissolved is $1.3\times 10^2g$

<u>Explanation:</u>

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

$\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m$

OR

$\text{Freezing point of pure solvent}=\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}$ ......(1)

where,

Freezing point of pure solvent = $-6.4^oC$

Freezing point of solution = $-13.6^oC$

i = Vant Hoff factor = 1 (for non-electrolytes)

$K_f$ = freezing point depression constant = $3.96^oC/m$

$m_{solute}$ = Given mass of solute (glycine) = ?

$M_{solute}$ = Molar mass of solute (glycine) = 75.07 g/mol

$w_{solvent}$ = Mass of solvent = 950. g

Putting values in equation 1, we get:

$-6.4-(-13.6)=1\times 3.96\times \frac{m_{solute}\times 1000}{75.07\times 950}\\\\m_{solute}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\m_{solute}=129.66g=1.3\times 10^2g$

Hence, the mass of glycine that can be dissolved is $1.3\times 10^2g$

5 0

3 years ago

A sample of sodium reacts completely with 0.213 kgkg of chlorine, forming 351 gg of sodium chloride. What mass of sodium reacted

lapo4ka [179]

Answer:

The mass of sodium reacted is 138 grams

Explanation:

Firstly, the chemical reaction should be represented with a balance chemical equation. The chemical equation can be written as follows.

Na = sodium

Cl2 = chlorine gas

Na + Cl2 → NaCl

The balanced equation is

2Na(s) + Cl2(g) → 2NaCl(aq)

Atomic mass of sodium = 23 grams per mol

Atomic mass of chlorine = 35.5 grams per mol

From the chemical equation the molar mass are as follows

Sodium = 2 × 23 = 46 grams

Chlorine = 35.5 × 2 = 71 grams

Sodium chloride = 2 × 23 + 2 × 35.5 = 117 grams

if 46 grams sodium reacted to produce 117 grams of sodium chloride

? grams of sodium react to produce 351 grams sodium chloride

grams of sodium reacted = (351 × 46)/117

grams of sodium reacted = 16146/117

grams of sodium reacted = 138 grams

6 0

3 years ago

Read 2 more answers

The tungsten- nuclide radioactively decays by alpha emission. Write a balanced nuclear chemical equation that describes this pro

Scrat [10]

Answer:

The solution to this question can be defined as follows:

Explanation:

The complete question is defined in the attached file.

$W^{180}_{74} \to He^{4}_{2} + Hf^{176}_{72}$

Here:

$W= Tungsten-180\\\\Hf =Hafnium\\\\He = \alpha \ particle\\\\$

5 0

3 years ago

Sam read that all subsystems interact with each other. Which example shows how changes in the cryosphere can affect the geospher

Dmitry_Shevchenko [17]

Answer:

Land that gains weight can rise slowly.

Explanation:

:D

7 0

3 years ago

Is ​oxygen and fluorine in the same family

Is oxygen and fluorine in the same family