Answer:
0.0280Kg/s
Explanation:
Given:
W = 1500
V2 = 300
V1 = 0
Q = 0 ( adiabatic)
T1 = 300
T2 = 20 m/s = converting to degrees we have 353°c
Let's use the energy equation

[/tex] m_• = W / (Cp(dT) + 0.5*V2^2) [/tex]


Answer:
784.090909mph
Explanation:
1ft/s=0.681818 mph
1150ft/s=0.681818 x 1150=784.090909
Answer:
First we must know the efficiency of the gearbox in which energy is lost by friction between its components, we divide this efficiency by the nominal power and find the real power.
With this value knowing the speed of rotation of the gearbox we select an engine that has a power just above.
Also keep in mind that the motor torque must be greater than the resistance offered by the gearbox and the 0.5Kw machine
Answer:
The digitization of performance management not only provides more precise data but also positively influences management processes and strategic development. Technology-enabled performance management tools simplify the manager's evaluation process and turn employees into active participants in their review sessions
Answer:
The result might require 9 bits to store