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mylen [45]
4 years ago
9

Assuming the torsional yield strength of a compression spring is 0.43Sut and the maximum shear stress is equal to 434MPa. What i

s the factor of safety if the spring is a music wire (A=2170MPa and m=0.146) with a wire diameter of 4mm?
Engineering
1 answer:
pav-90 [236]4 years ago
4 0

Answer:

factor of safety is 1.756

Explanation:

given data

torsional yield strength = 0.43 sut  

maximum shear stress = 434 MPa

A = 2170 MPa

m = 0.146

diameter = 4 mm

to find out

factor of safety

solution

we know 1 sut is equal to 1772.39 MPa

so 0.43 sut = 0.43 ×1772.39 =  762.128 MPa

so here

factor of safety formula is

factor of safety = yield strength / shear stress   ............1

put here value

factor of safety = 762.128 / 434

factor of safety is 1.756

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Answer:

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Explanation:

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That is, the value of the number mod 9 (or 3) is 2.

The ones digit is odd, so the value of the number mod 2 is 1.

This combination of modulo values tells you the mod 6 result is 5.

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<em>Additional comment</em>

We can look at the (mod2, mod3) values of the numbers 0 to 5:

  0 ⇒ (0, 0)

  1 ⇒ (1, 1)

  2 ⇒ (0, 2)

  3 ⇒ (1, 0)

  4 ⇒ (0, 1)

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This process of adding up the digits repeatedly is referred to as "casting out 9s." The result of it is the modulo 9 value of the number (with 0 mapped to 9). Checking the mod 9 result of arithmetic operations is one quick way to spot certain kinds of errors. It can also be used as part of a divisibility test for 3 or 9.

3 0
3 years ago
List irreversibilities
natali 33 [55]

Answer:

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6 0
3 years ago
How to calculate maximum shear stress in the cross-section of a beam if the neutral axis is not on the thinnest part of the cros
likoan [24]

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Yes.

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1 year ago
Calculate the reluctance of a 4-meter long toroidal coil made of low-carbon steel with an inner radius of 1.75 cm and an outer r
My name is Ann [436]

Answer:

R = 31.9 x 10^(6) At/Wb

So option A is correct

Explanation:

Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A

Thus; R = L/μA,

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L = 4m

r_1 = 1.75cm = 0.0175m

r_2 = 2.2cm = 0.022m

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A = π(0.0225)² - π(0.0175)²

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We are given that;

L = 4m

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Thus, reluctance is calculated as;

R = 4/(2 x 10^(-4) x 6.28x 10^(-4))

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R = 31.9 x 10^(6) At/Wb

8 0
4 years ago
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