Answer:
The acceleration of the proton is 9.353 x 10⁸ m/s²
Explanation:
Given;
speed of the proton, u = 6.5 m/s
magnetic field strength, B = 1.5 T
The force of the proton is given by;
F = ma = qvB(sin90°)
ma = qvB
where;
m is mass of the proton, = 1.67 x 10⁻²⁷ kg
charge of the proton, q = 1.602 x 10⁻¹⁹ C
The acceleration of the proton is given by;
Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²
<h2><em>state coulombs law in word</em></h2>
- <em>: a statement in physics: <u>the force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between </u></em><em><u>them</u></em>
<em><u>hope </u></em><em><u>it</u></em><em><u> helps</u></em>
<em><u>#</u></em><em><u>c</u></em><em><u>a</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>on</u></em><em><u> learning</u></em>
To solve this there is this website that I found that helps
I am in middle school so I have no idea how to solve this
but
this website may help considering u are in high school and u
(hopefully mind u)
know how to solve this
so to get there u google
"whats impact speed"
and click on the first thing there the website is ehow
-0 m/s
- average velocity=displacement/time
- the runners displacement is zero so her average velocity must be zero
The force needed to accelerate a vehicle with a mass of 1000kg at a rate of 5m/s2 would be 5000
