88.98 %
The Balance Chemical Equation is as follow,
2 HCl + Pb(NO₃)₂ → 2 HNO₃ + PbCl₂
According to equation,
331.2 g (1 mole) Pb(NO₃)₂ produces = 278.1 g (1 mole) PbCl₂
So,
870 g of Pb(NO₃)₂ will produce = X g of PbCl₂
Solving for X,
X = (870 g × 278.1 g) ÷ 331.2 g
X = 730.5 g of PbCl₂
Therefore,
Theoretical Yield = 730.5 g
Also as given,
Actual Yield = 650 g
So using following formula for percentage yield,
%age Yield = (Actual Yield / Theoretical Yield) × 100
Putting values,
%age Yield = (650 g / 730.5 g) × 100
%age Yield = 88.98 %
Brianliest please and thank you.
Answer:

The reactant that is reduced is 
Explanation:
The complete equation is as below:

<em>Recall that oxidation involves the gain of electrons while reduction involves the loss of electrons.</em>
In the above reaction,
loses electrons to coenzyme Q and becomes reduced to FAD, hence the oxidizing agent. Coenzyme Q gains electrons and becomes oxidized to
, hence the reducing agent.
<u>In order words, </u>
<u> is reduced while coenzyme Q is oxidized.</u>
Answer:
it needs two electrons in the first and eight to fill the second.
Explanation:
Because neon has two atomic shells, it needs two electrons in the first and eight to fill the second. Neon has a total of ten electrons which means two filled shells.
Answer:
65.18% is the percent yield for this reaction.
Explanation:

Moles of salicyclic acid = 
According to reaction 1 mole of salicyclic acid gives 1 mole of aspirin .
Then 0.01449 mole of salicylic acid will give :
of asprin
Mass of 0.01449 moles of aspirin :
= 0.01449 mol × 180 g/mol = 2.6082 g
Theoretical yield of aspirin = 2.6082 g
Experimental yield of aspirin = 1.7 g
The percent yield for this reaction:


65.18% is the percent yield for this reaction.
Answer:

Explanation:
Hello there!
In this case, according to this question, we will need to deal with this dilution problem, because it is asking for the volume of a 12.1-M stock solution of HCl. In such a way, we can use the following equation, under the assumption of no change in the number of moles in the solution:

Thus, we solve for the initial volume, V1, as shown below:

And plug in the initial concentration and final concentration and volume to obtain:

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