I am just answering so u can mark the other guy brainliest
Solubility <span>is a measurement that describes how much solute dissolves in a given amount of solvent</span>
Hey there!:
moles of AgNO3 = 100 x 0.1 / 1000 = 0.01
moles of NaCl = 100 x 0.200 / 1000 = 0.02
volume of solution = 100 + 100 = 200 mL
mass of solution = 200 x 1 = 200 g
temperature rise = 25.30 - 24.60 = 0.70ºC
Therefore:
Q = m* Cp* ΔT + Cp* ΔT =
200* 4.184 * 0.70 + 15.5 * 0.70 =
Q = 596.61 J
Given the reaction:
Q = 596.61 J
NaCl(aq) + AgNO3(aq)--------> AgCl(s) + NaNO3(aq)
1 mole NaCl ------ 1 mole AgNO3 ------ 1 mole AgCl
0.02 moles NaCl ----- 0.01 moles AgNO3
So:
ΔH = - Q / T
ΔH = - 596.61 * 10⁻³ / 0.01
ΔH = - 59.66 kJ
Hope that helps!
