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astra-53 [7]
2 years ago
15

Can i eat unhealthy while i’m drinking green tea for weight loss ?

Engineering
2 answers:
Zina [86]2 years ago
6 0

Answer:I don't think it's a better idea to eat unhealthy food while having green tea because it will act as a strumbling rock in your attempt of getting weight loss.

Explanation:I don't say you have to mark my ans as brainliest but if ypu think it has really helped you plz don't forget to thank me...

storchak [24]2 years ago
6 0
Weight loss treatments vary among all people. Any health improvements could help, but I don’t think this plan is meant for fast action results.
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What is the sun's degree angle in the sky in summer and in winter?
Vladimir [108]

Answer:

At the time of the summer or winter solstices, the Sun is 23.44° degrees above or below the horizon, respectively, irrespective of time of day.

Explanation:

6 0
2 years ago
Water from the Earth's surface turns into a gas, or water vapor, when it is warmed and
bagirrra123 [75]

Answer:

Evaporation.

Explanation:

Evaporation is the stage of the Water Cycle where water turns into water vapor. The steps following Evaporation in order include Condensation, Precipitation, and Transpiration.

4 0
3 years ago
Read 2 more answers
Railroad tracks made of 1025 steel are to be laid during the time of year when the temperature averages 4C (40F). Of a joint spa
DENIUS [597]

Answer:

41.5° C

Explanation:

Given data :

1025 steel

Temperature = 4°C

allowed joint space = 5.4 mm

length of rails = 11.9 m

<u>Determine the highest possible temperature </u>

coefficient of thermal expansion ( ∝ ) = 12.1 * 10^-6 /°C

Applying thermal strain ( Δl / l )  = ∝ * ΔT

                                    ( 5.4 * 10^-3 / 11.9 )  = 12.1 * 10^-6 * ( T2 - 4 )

∴  ( T2 - 4 ) =  ( 5.4 * 10^-3 / 11.9 ) / 12.1 * 10^-6

hence : T2 = 41.5°C

8 0
3 years ago
Can you answer what is attached.
kirill [66]
29.4 bro I hope that helps
3 0
3 years ago
A pipe of 0.3 m outer diameter at a temperature of 160°C is insulated with a material having a thermal conductivity of k = 0.055
Alekssandra [29.7K]

Answer:

Q=0.95 W/m

Explanation:

Given that

Outer diameter = 0.3 m

Thermal conductivity of material

K= 0.055(1+2.8\times 10^{-3}T)\frac{W}{mK}

So the mean conductivity

K_m=0.055\left ( 1+2.8\times 10^{-3}T_m \right )

T_m=\dfrac{160+273+40+273}{2}

T_m=373 K

K_m=0.055\left ( 1+2.8\times 10^{-3}\times 373 \right )

K_m=0.112 \frac{W}{mK}

So heat conduction through cylinder

Q=kA\dfrac{\Delta T}{L}

Q=0.112\times \pi \times 0.15^2\times 120

Q=0.95 W/m

4 0
3 years ago
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