Answer:
(a) 11.437 psia
(b) 13.963 psia
Explanation:
The pressure exerted by a fluid can be estimated by multiplying the density of the fluid, acceleration due to gravity and the depth of the fluid. To determine the fluid density, we have:
fluid density = specific gravity * density of water = 1.25 * 62.4 lbm/ft^3 = 78 lbm/ft^3
height = 28 in * (1 ft/12 in) = 2.33 ft
acceleration due to gravity = 32.174 ft/s^2
The change in pressure = fluid density*acceleration due to gravity*height = 78*32.174*(28/12) = 5855.668 lbm*ft/(s^2 * ft^2) = 5855.668 lbf/ft^2
The we convert from lbf/ft^2 to psi:
(5855.668/32.174)*0.00694 psi = 1.263 psi
(a) pressure = atmospheric pressure - change in pressure = 12.7 - 1.263 = 11.437 psia
(b) pressure = atmospheric pressure + change in pressure = 12.7 + 1.263 = 13.963 psia
B) the plates are in constant motion and as a result the boundaries are where they interact
Answer:
Q = 8.845 DEGREE
Explanation:
given data:
combine Mass for 6 cylinder (M) =15 Kg/hr
mass of each cylinder (m) = 15/6 = 2.5 Kg/hr = 0.000694 Kg/ sec
Engine speed (N)= 1500rpm
Diameter of one nozzle hole ( d) = 200 micrometer = 0.0002 m
Discharge Coefficient (Cd) = 0.75
Pressure difference = 100 MPa
Density of fuel = 800 kg/m^3
velocity of fuel is 
injected fuel volume (V) =Area of given Orifices × Fuel velocity × time of single injection × no of injection/sec
we know that p = m/ V
So
putting these value in volume equation and solve for Discharge 
Q = 8.845 DEGREE
Answer:
A.
Explanation:
Able to return to it's original shape after distortion.
Answer:
Compute the first four central moments for the following data:
i xi
1 45
2 22
3 53
4 84Explanation:
