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umka2103 [35]
3 years ago
9

So far in this tutorial, you have been launching a pumpkin. Let's see what happens to the trajectory if you launch something big

ger and heavier, like a car. Compare the trajectory and range of the pumpkin to that of the car, using the same initial speed and angle (e.g., 45∘). (Be sure that air resistance is still turned off.) Which statement is true? So far in this tutorial, you have been launching a pumpkin. Let's see what happens to the trajectory if you launch something bigger and heavier, like a car. Compare the trajectory and range of the pumpkin to that of the car, using the same initial speed and angle (e.g., ). (Be sure that air resistance is still turned off.) Which statement is true? The trajectories differ; the range of the car is longer than that of the pumpkin. The trajectories differ; the range of the car is shorter than that of the pumpkin. The trajectories and thus the range of the car and the pumpkin are identical.
Physics
1 answer:
Sliva [168]3 years ago
3 0

Answer:

The trajectories and thus the range of the car and the pumpkin are identical.

Explanation:

Trajectory of projectile is given by

Y=x \tan \theta-\frac{gx^2}{2u^2 \cos \theta ^2}

Also range is given by,

R=\frac{u^2 \sin 2 \theta}{g}

Trajectory and path both are independent on mass. Only depends on initial speed u and angle of projection \theta

So Range and Trajectory both will be same.

Identical trajectory and equal range.

Therefore, The trajectories and thus the range of the car and the pumpkin are identical.

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